Physics Ncert Solutions Class 12th

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New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

M? = 200MeV/C², m = 1Gev/C²
Initial velocity of particle is 'V'.
Final velocity of hydrogen atom is 'V'
M? V? = mV
V = M? V? /m
Also, 1/2 M? V? ² = 1/2 mV² + 3/4 x 13.6
Put (1) and get answer
1/2 M? V? ² = 51/4 eV
Hence, N = 51.

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

Power delivered = 1000 W
Voltage = 220 V
Transmission 'I' = 1000/220
Power loss = I²R
Efficiency = (1000x100)/ (1000 + I²R)

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

ln |R| = ln|R? | - λt
and T? /? ∝ 1/λ
where 'N' is slope
V² = 2gh
h = √2gh
h = -√2gh + gt²/2
gt² - 2√2ght - 2h = 0
t = (2√2gh ± √ (8gh + 8gh)/2g
t = (2√2gh + 4√gh)/2g as cannot be negative.
∴ t = (2 + √2)√ (h/g) → 3.4√ (h/g)
T? /? (A):T? /? (B):T? /? (C) = 10/6 : 5/6 : 5/2 = 2:1:3

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

5 months ago

0 Follower 20 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

5 months ago

0 Follower 9 Views

A
alok kumar singh

Contributor-Level 10

Uinitial = k(4q)(q)/(d/2) + k(q)(-q)/(d/2)
⇒ 6kq²/d
⇒ Ufinal = k(4q)(q)/((3d/2)) + k(q)(-q)/(d/2)
⇒ 2kq²/3d
⇒ ΔU = (2/3 - 6)kq²/d = -16kq²/3d

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