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New answer posted

a year ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

F→=10i^+5j^

a→=10mi^+5mj^

=100.1kgi^+50.1j^

a→=100i^+50j^

ax=100, ay=50

Sx=ut+12at2

=0*2+12*100*2*2

Sx = 200 m

ab=200100=2

New answer posted

a year ago

0 Follower 10 Views

P
Payal Gupta

Contributor-Level 10

Given, L = 2H

l = 2 sin (t2)

u = ∫ 0 2 L i d i = L 2 [ i 2 ] 0 2 = L 2 [ 4 − 0 ]

u = 2 2 * 4 = 4 J

New answer posted

a year ago

0 Follower 23 Views

P
Payal Gupta

Contributor-Level 10

≡ R e q = 2 . 5 Ω

l = v R e q = 5 2 . 5 = 2 A

New answer posted

a year ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

 H=I2Rt=22*R*15

⇒300=60R

R=5Ω

Now for 3A, time = 10 sec

H'=l2Rt=32*5*10=450J

New answer posted

a year ago

0 Follower 12 Views

P
Payal Gupta

Contributor-Level 10

2 4 * 8 3 2 = 6 μ F

New answer posted

a year ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

H=λ4

⇒20=λ4

λ=80cm

Now first overtone for open organ pipe

L2=4λ4=λ=80  cm

New answer posted

a year ago

0 Follower 5 Views

P
Payal Gupta

Contributor-Level 10

Q1=20°Cwater→100°  steam

Q1=mcΔT+mL

=m [cΔT+L]

=31000=31*103cal

Q2=293373*31*103

= 2 4 . 3 5 * 1 0 3 c a l

New answer posted

a year ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

τ=ηvh

Given

τ=10−3N/m2

(shear stress)

h =?

v = 36 km/hr = 10 m/sec

10−3=10−2*10h

h = 100 m

New answer posted

a year ago

0 Follower 5 Views

P
Payal Gupta

Contributor-Level 10

by conservation of mechanical energy

K.Ei + P.Ei = K.Ef + P.Ef

12*0.5v2+0=12*0.5 (v2)2+12kx2

⇒12*0.5 [v2−v24]=12kx2

⇒1.5412*12=k*9100

1.5*369*100=k

k = 600 N/m1

New answer posted

a year ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

F.B.D. of hanging length

F.B.D. of chain lying on the table

f = T = μN

⇒λxg=μλ (L−x)g

x=0.5 (6−x)

⇒x=3−0.5x

1.5x=3

x = 2m

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