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New answer posted
a year agoContributor-Level 10
2.32
Distance of the moon from Earth = 3.84 * 108 m
Distance of the Sun from Earth = 1.496 * 1011 m
Sun's diameter = 1.39 * 109 m
Sun's angular diameter = 1920° = 1920 * 4.85 * 10-6 rad = 9.3 * 10-3 rad
During total Solar eclipse, the moon completely covers the Sun, then the angular diameter of both Sun and the
Moon will be equal
So the angular diameter of moonΘ = 9.3 * 10-3 rad, distance d of moon from Earth = 3.84 * 108 m and
diameter of the moon = angular diameter * distance
So the approximate diameter of the Moon = 9.3 * 10-3 * 3.84 * 108 m = 35.712 * 105 m
New answer posted
a year agoContributor-Level 10
2.31
Speed of light = 3 * 108 m/s, Time taken = 3 billion years = 3 * 109 years = 3 * 365 * 24 * 60 * 60 * 109 s
The distance = speed x time = 3 * 108 * 3 * 365 * 24 * 60 * 60 * 109 m
= 2.838 * 1025 m
New answer posted
a year agoContributor-Level 10
2.30
Speed of the sound in water = 1450 m s–1
Time taken from generation + reflection = 2t = 77 s
From the relation s = ut, where s is the distance of the enemy ship, we get
s = 1450 * 77/2 m = 55825 m = 55.8 km
New answer posted
a year agoContributor-Level 10
2.29 Time taken by the laser beam after reflection = 2.56 s
The speed of laser = 3 * 108 m/s
If the distance between Earth and the Moon is d, the distance covered by laser beam is 2d
From the relation distance = speed * time, we get
d = (2.56 * 3 * 108)/2 = 3.84 * 108 m
New answer posted
a year agoContributor-Level 10
2.27
The diameter of the sodium atom = 2.5 Å = 2.5 * 10-10 m
Radius of the sodium atom = 1.25 * 10-10 m
Volume of the sodium atom = (4/3)(π) r3 = (4/3) * (22/7) * (1.25 * 10-10) m3 = 8.18 * 10-30
Mass of 1 mole atom of sodium = 23 g = 23 * 10-3 kg
1 mole of sodium contains 6.023 * 1023 atoms.
Hence mass of 1 sodium atom = (23 * 10-3)/ (6.023 * 1023) = 3.818 * 10-26 kg
Atomic mass density of sodium = M/V = (3.818 * 10-26)/ (8.18 * 10-30) kg/m3 = 4667.48 kg/m3
The density of sodium in its solid state is 4667.48 kg/m3 but in the crystalline phase is 970 kg/m3.
In crystalline phase there are voids in between atoms, hence the density
New answer posted
a year agoContributor-Level 10
2.26
Total time in 100 years = 100 * 365 * 24 * 60 * 60 s
Error in 100 years = 0.02 sec
Error in 1 sec= 0.02 / (100 * 365 * 24 * 60 * 60) s = 6.34 * 10-12
New answer posted
a year agoContributor-Level 10
2.25 In the equation v = tan(θ) , the dimension v = L1T-1. Since tan? is dimensionless, the equation v = tan(θ) is incorrect.
To make it correct v must be divided by the velocity of rain u and the correct expression should be v/u = tan(θ)
New answer posted
a year agoContributor-Level 10
2.23
Mass of the Sun = 2.0 * 1030 kg
Radius of the Sun = 7.0 * 108 m
Volume of the Sun = (4/3)(π) r3 = 4/3 x(π) x (7.0 * 108)3 = 1.436 * 1027
Density of the Sun = Mass / volume = 2.0 * 1030 kg / 1.436 * 1027 kg/ m3 = 1.39 * 103 kg/ m3
The density is in the range of solids and liquids.
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