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New answer posted

11 months ago

0 Follower 221 Views

V
Vishal Baghel

Contributor-Level 10

This question belongs to the Motion in a straight line chapter that we will be solving this with explanation.

(a) A railway carriage moving without jerks between two stations

Whenever a railway carriage moves between two stations smoothly without jerks, it is considered as a point object. This is due to the fact that distance between the two stations is larger as compared to the size of carriage. However, we are interested in the overall motion instead of the movement of specific parts of carriage.

(b) A monkey sitting on top of a man cycling smoothly on a circular track

Here, both monkey as well as the cyclist are considered as a single p

...more

New answer posted

11 months ago

0 Follower 32 Views

V
Vishal Baghel

Contributor-Level 10

2.32

Distance of the moon from Earth = 3.84 * 108 m

Distance of the Sun from Earth = 1.496 * 1011 m

Sun's diameter = 1.39 * 109 m

Sun's angular diameter = 1920° = 1920 * 4.85 * 10-6 rad = 9.3 * 10-3 rad

During total Solar eclipse, the moon completely covers the Sun, then the angular diameter of both Sun and the

Moon will be equal

So the angular diameter of moonΘ = 9.3 * 10-3 rad, distance d of moon from Earth = 3.84 * 108 m and

diameter of the moon = angular diameter * distance

So the approximate diameter of the Moon = 9.3 * 10-3 * 3.84 * 108 m = 35.712 * 105 m

New answer posted

11 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

2.31

Speed of light = 3 * 108 m/s, Time taken = 3 billion years = 3 * 109 years = 3 * 365 * 24 * 60 * 60 * 109 s

The distance = speed x time = 3 * 108 * 3 * 365 * 24 * 60 * 60 * 109 m

= 2.838 * 1025 m

New answer posted

11 months ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

2.30

Speed of the sound in water = 1450 m s–1

Time taken from generation + reflection = 2t = 77 s

From the relation s = ut, where s is the distance of the enemy ship, we get

s = 1450 * 77/2 m = 55825 m = 55.8 km

New answer posted

11 months ago

0 Follower 31 Views

V
Vishal Baghel

Contributor-Level 10

2.29 Time taken by the laser beam after reflection = 2.56 s

The speed of laser = 3 * 108 m/s       

If the distance between Earth and the Moon is d, the distance covered by laser beam is 2d

From the relation distance = speed * time, we get

d = (2.56 * 3 * 108)/2 = 3.84 * 108 m

New answer posted

11 months ago

0 Follower 25 Views

V
Vishal Baghel

Contributor-Level 10

Kindly go through the solution

New answer posted

11 months ago

0 Follower 27 Views

V
Vishal Baghel

Contributor-Level 10

2.27

The diameter of the sodium atom = 2.5 Å = 2.5 * 10-10 m

Radius of the sodium atom = 1.25 * 10-10 m

Volume of the sodium atom = (4/3)(π) r3 = (4/3) * (22/7) * (1.25 * 10-10)  m3 = 8.18 * 10-30

Mass of 1 mole atom of sodium = 23 g = 23 * 10-3 kg

1 mole of sodium contains 6.023 * 1023 atoms.

Hence mass of 1 sodium atom = (23 * 10-3)/ (6.023 * 1023) = 3.818 * 10-26 kg

Atomic mass density of sodium = M/V = (3.818 * 10-26)/ (8.18 * 10-30) kg/m3 = 4667.48  kg/m3

The density of sodium in its solid state is 4667.48 kg/m3 but in the crystalline phase is 970 kg/m3.

In crystalline phase there are voids in between atoms, hence the density

...more

New answer posted

11 months ago

0 Follower 11 Views

V
Vishal Baghel

Contributor-Level 10

2.26

Total time in 100 years = 100 * 365 * 24 * 60  * 60 s

Error in 100 years = 0.02 sec

Error in 1 sec= 0.02 / (100 * 365 * 24 * 60  * 60) s = 6.34 * 10-12

New answer posted

11 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

2.25 In the equation v = tan(θ) , the dimension v = L1T-1. Since tan? is dimensionless, the equation v = tan(θ) is incorrect.

To make it correct v must be divided by the velocity of rain u and the correct expression should be v/u = tan(θ)

New answer posted

11 months ago

0 Follower 17 Views

V
Vishal Baghel

Contributor-Level 10

Kindly go through the solution

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