Physics

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New answer posted

8 months ago

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A
Aadit Singh Uppal

Contributor-Level 10

Infrared radiation is a part of the electromagnetic spectrum which is specifically used in night detection techniques to enhance visibility. They have a wavelength of around 700 nm to 1 mm and have a frequency range of around 10^12 Hz.

New answer posted

8 months ago

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A
Aadit Singh Uppal

Contributor-Level 10

There are different types of electromagnetic waves and each of them have different wavelengths. Human eye can only see the light rays which have a minimum wavelength of around 400-700nm. Rays which don't meet this threshold will eventually not be visible to the humans.

New answer posted

8 months ago

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Vishal Baghel

Contributor-Level 10

? 1 = 3 5 E 0 ( 0 . 2 ) N m 2 C 1 , a n d ? 2 = 4 5 E 0 ( 0 . 3 ) N m 2 C 1

? 1 ? 2 = 3 * 0 . 2 * 5 5 * 0 . 3 * 4 = 1 2

New answer posted

8 months ago

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Aadit Singh Uppal

Contributor-Level 10

It depends on the frequency of the wave. Rays such as Gamma rays, X-Rays etc. have higher frequencies which can lead to harmful impacts if exposed to the human body. These kind of rays cannot be even produced easily unlike low frequency rays.

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8 months ago

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Vishal Baghel

Contributor-Level 10

Let v is velocity at the highest position.

T m a x = 5 T m i n m g + m ( v 2 + 4 g l ) l = 5 ( m v 2 l m g ) 4 . v 2 l = 1 0 g

v = 5 2 g l = 5 2 * 1 0 * 1 = 5 m / s

New answer posted

8 months ago

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Vishal Baghel

Contributor-Level 10

Δ U + Δ K E = 0

f 2 n R Δ T = 1 2 m v 2 Δ T = m n v 2 f R = 4 * 1 0 3 * 3 0 2 3 R = 3 . 6 3 R K .

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8 months ago

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Pallavi Pathak

Contributor-Level 10

The following are the topics covered in this chapter: Electric Field and Field Lines, Gauss's Law, Electric Dipole, Conductors and Insulators, and Electric Flux. 

New answer posted

8 months ago

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Vishal Baghel

Contributor-Level 10

For equilibrium,

d U d r = 0 1 0 α r 1 1 + 5 β r 6 = 0 r = ( 2 α β ) 1 5

New answer posted

8 months ago

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Vishal Baghel

Contributor-Level 10

L d i d t = V 2 d i = 3 t d t 2 0 i d i = 3 0 4 t d t i = 1 2 A

U = 1 2 L i 2 = 1 2 * 2 * 1 2 2 = 1 4 4 J

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8 months ago

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Pallavi Pathak

Contributor-Level 10

For JEE Main exam, the Electric Charges and Fields is an important chapter. It is a part of Electrostatics unit. The weightage of this unit is around 6-9% of the total Physics section. You should expect around 3-5 questions in this unit including the questions from the class 12 physics chapter 1.

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