Chemistry NCERT Exemplar Solutions Class 11th Chapter Eight
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New answer posted
7 months agoContributor-Level 10
This is a Long answer type question as classified in NCERT Exemplar
Disproportionate is defined as the reaction in which one compound of intermediate oxidation state converts to two compounds, one of higher and one of lower oxidation states So, to occur such type of redox reaction, the element should exist in at least three oxidation states. So that element present in the intermediate state and it can change to both higher and lower oxidation state during disproportionate reaction. Fluorine is the most electronegative element and a strong oxidizing agent and is the smallest in size of all the halogens. It does not show a positive oxidat
New answer posted
7 months agoContributor-Level 10
This is a Long answer type question as classified in NCERT Exemplar
On the basis of standard reduction potential suggested in the reactivity series (ii) reaction can take place as Mg has more negative value of E? cell. Hence, Mg will be oxidized by losing electron and iron will be reduced by gaining electron.
New answer posted
7 months agoContributor-Level 10
This is a Long answer type question as classified in NCERT Exemplar
The given reaction is a redox change.
2Na (s)+H2 (g)→2NaH (s)
The half reaction is:
2Na (s)→2Na+ (g)+2e-
The other half reaction is:
H2 (g)+2e-→2H- (g)
This splitting of the reaction into two half-reactions automatically reveals here that sodium is oxidized, and hydrogen is reduced. Any substance which loses electron is oxidized and gains electron is reduced hence is the case of sodium and hydrogen atoms respectively. Hence, the complete reaction is a redox change.
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