Chemistry NCERT Exemplar Solutions Class 11th Chapter Eight

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A
alok kumar singh

Contributor-Level 10

Number of mole of X = 6.022 * 10 22 6.022 * 10 23 = 10   Molar mass of   X

So molar mass of X = 100 g

Molarity = 5 100 * 2 = 0.025 M

Ans. = 0.025 M

M = 25 * 10 - 3

So P = 25

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a month ago

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A
alok kumar singh

Contributor-Level 10

According to Faraday law

  W = Z I t * η Where η = efficiency

or W = E 96500 * 1 * t * η

Putting values

. 104 = ( 52 / 3 ) * 2 * 8 * 60 * η 96500 η = 0.6

So percentage efficiency = 60 %

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a month ago

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A
alok kumar singh

Contributor-Level 10

For isotonic solution

i 1 C 1 = i 2 C 2 ffor protein i = 1

C 1 = C 2

0.73 * 1000 M A * 250 = 1.65 M B * 1

M A M B = 0.73 * 4 1.65 = 1.77 = 177 * 10 - 2

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A
alok kumar singh

Contributor-Level 10

Asp - Glu - Lys pripeptide is:

No. of C O group = 5

 

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alok kumar singh

Contributor-Level 10

Phosphinic acid is hypo phosphorous acid H 3 P O 2 .

N a O H + H 3 P O 2 ? N a H 2 P O 2 + H 2 O

For neutrization

N 1 V 1 acid   = N 2 V 2 base  

0.1 * 10 = 0.1 * V m L N a O H

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alok kumar singh

Contributor-Level 10

K = 3.3 * 10-4 s-1

Time for 40% completion ; t

Using K = 2 . 3 0 3 t l o g 1 0 [ R ] 0 [ R ]  

3.3 * 10-4 =   2 . 3 0 3 t l o g 1 0 [ R ] 0 0 . 6 [ R ] 0

t = 2 . 3 0 3 3 . 3 * 1 0 4 * 0 . 2 2 t = 2 5 . 5 8 m i n s  

so; the nearest integer is 26.

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alok kumar singh

Contributor-Level 10

Coordination no. of an atom in BCC is 8.

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alok kumar singh

Contributor-Level 10

Using λ = h 2 q V m  

λ L i = h 2 * 3 e * V * 8 . 3 m                 m = mass of proton

λ p = h 2 * e * V * m  

λ L i λ p = 2 e V m 2 * 2 4 . 9 e V m            

= 0.2 = 2 * 10-1

So; x = 2

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a month ago

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alok kumar singh

Contributor-Level 10

W = 4.5 g

M.W = 90

V = 250 ml

Using M = W M . W * V * 1 0 0 0  

M = 4 . 5 9 0 * 2 5 0 * 1 0 0 0 = 0 . 2  

M = 2 * 10-1 M

So, x = 2

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a month ago

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A
alok kumar singh

Contributor-Level 10

The balanced equation is :

S 8 ( s ) + 1 2 O H ( a q ) 4 S 2 ( a q ) + 2 S 2 O 3 2 ( a q ) + 6 H 2 O ( l )           

Here ; a = 12

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