Chemistry NCERT Exemplar Solutions Class 11th Chapter Five
Get insights from 52 questions on Chemistry NCERT Exemplar Solutions Class 11th Chapter Five, answered by students, alumni, and experts. You may also ask and answer any question you like about Chemistry NCERT Exemplar Solutions Class 11th Chapter Five
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
(a) HCl, HBr and HI have dipole-dipole and london dispersion interaction whereas HF has hydrogen bonding in addition (due to the high electronegativity of the F atom).
(b) The electronegativity decreases from Cl, Br and I so the dipole-dipole interaction will also decrease as HCl > HBr > HI and it is contrary to the boiling point order which is HCl < HBr < HI. This confirms that the London interaction is predominant.
(c) F atom has the highest electronegativity so it has hydrogen bonding interaction in addition to dipole-dipole and london dispersion interaction which leads to the highest boiling poi
New answer posted
4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
The factors that determine the states of matter are:
1. Temperature
2. Pressure
3. Mass and volume
New answer posted
4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
Physical state of ice, water and steam are very different but the chemical composition of water in all the three states is H2O.
New answer posted
4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
(a) the greatest volume is occupied by CH4 and
(b) the smallest volume by NO
According to Avagadro's Law,
Volume of 1 mole of a gas at STP = 22.4 L
Now, we know,
1 mole = Molar mass
∴ Volume of 28g mol-1 of CO at STP = 22.4 L
So, Volume of 1 g of CO at STP = 22.4 L / 28 g mol-1
Similarly,
Volume of 1 g of H2O at STP = 22.4 L / 18 g mol-1
Volume of 1 g of CH4 at STP = 22.4 L / 16 g mol-1 (
New answer posted
4 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
Option (ii). Adding salt to water and
(iv). Decreasing the temperature of water
By adding salt to water, the water molecule available at the surface to evaporate will be low and hence, the vapour pressure decreases. Also vapour pressure is directly proportional to temperature so when we decrease the temperature of water the vapour pressure decreases.
New answer posted
4 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
option (ii). High pressure and
(iii). Low temperature
The real gases obey the ideal gas equation, PV= nRT at low pressure and high temperature. So, a gas does not obey the ideal gas equation or behave ideally at high pressure and low temperature.
New answer posted
4 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
Option (i). 16 grams of gas and
(iv). 11.2 litres of gas
1 mole of dioxygen at STP occupies = 22.4 L
molar mass of dioxygen = 32 g
contain 6.023*1023 molecules of oxygen gas
New answer posted
4 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
Option (ii). Complete disorder of molecules and
(iii). Random motion of molecules
In a gaseous state of matter, molecules are arranged in complete disorder and they move in random motion in all directions.
New answer posted
4 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
Option (ii). Decreases
When the temperature increases, kinetic energy of the molecule increases which leads to decrease in the intermolecular forces and hence, decreases the surface tension.
New answer posted
4 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
Option (iii) Decrease
The increase in temperature increases the kinetic energy which can overcome intermolecular forces of attraction due to which the viscosity decreases and the liquid starts flowing.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 679k Reviews
- 1800k Answers
