Chemistry

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New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

In Fe0.93O

Let us suppose that fraction of Fe2+ is x and fraction of Fe3+ is (1 – x)

x * ( + 2 ) + ( 1 − x ) * ( + 3 ) = O.S. of Fe atom

o r     2 x + 3 − 3 x = + 2 0 0 9 3

∴ %     o f     F e 2 + = 8 5 %     a n d     %     o f     F e 3 + = 1 5 %

New answer posted

a year ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

In Fe0.93O

Let us suppose that fraction of Fe2+ is x and fraction of Fe3+ is (1 – x)

x * ( + 2 ) + ( 1 ? x ) * ( + 3 ) = O.S. of Fe atom

o r ? ? 2 x + 3 ? 3 x = + 2 0 0 9 3

? % ? ? o f ? ? F e 2 + = 8 5 % ? ? a n d ? ? % ? ? o f ? ? F e 3 + = 1 5 %

New answer posted

a year ago

0 Follower 13 Views

P
Payal Gupta

Contributor-Level 10

Consider the image below

 

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

Moles of H C l = moles of N H 3

= 2 * moles of urea = 2 * 0.6 60 = 0.02

⇒ N . V = 0.02

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

Conceptual.

New question posted

a year ago

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New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a year ago

0 Follower 8 Views

P
Payal Gupta

Contributor-Level 10

Consider the image below

New answer posted

a year ago

0 Follower 12 Views

P
Payal Gupta

Contributor-Level 10

Consider the image given below

New answer posted

a year ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

Based upon the properties and uses of chemical substances.

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