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Chemistry NCERT Class 12 Chemistry

Given below are two statements.

Statement I: The chlorides of Be and Al have Cl-bridged structure. Both are soluble in organic solvents and act as Lewis bases.

Statement II: Hydroxides of Be and Al dissolve in excess alkali to give beryllate and aluminate ions.

In the light of the above statements, choose the correct answer form the options given below.

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alok kumar singh

Contributor-Level 10

Be₂Cl₄ is Lewis acid and Al₂Cl₆ has complete octet. Be and Al are amphoteric metal therefore dissolve in acid as well as alkaline solution and form beryllate and aluminate ions in excess alkali.

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Chemistry Class 11th

Given below are two statements.

Statement I: Hydrogen peroxide can act as an oxidizing agent in both acidic and basic conditions.

Statement II: Density of hydrogen peroxide at 298 K is lower than that of D₂O.

In the light of the above statements, choose the correct answer from the options given below.

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alok kumar singh

Contributor-Level 10

Depending on the nature of reducing agent H₂O₂ can act as oxidizing agent in both acidic as well as basic medium.

Density of D₂O = 1.1 gm/cc

Density of D₂O₂ = 1.45 gm/cc

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8 months ago

Chemistry Class 12th

Which of the following methods are not used to refine any metal?

(A). Liquation

(B). Calcination

(C). Electrolysis

(D). Leaching

(E). Distillation

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alok kumar singh

Contributor-Level 10

Calcination and leaching are the methods of concentration of ores and not that of refining.

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Chemistry Class 11th

The incorrect statement is

(a) The first ionization enthalpy of K is less than that of Na and Li

(b) Xe does not have the lowest first ionization enthalpy in its group

(c) The first ionization enthalpy of element with atomic number 37 is lower than that of the element with atomic number 38.

(d) The first ionization enthalpy of Ga is higher than that of the d-block element with atomic number 30.

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alok kumar singh

Contributor-Level 10

Ionisation enthalpy order :

Li > Na > K

He > Ne > Ar > Kr > Xe > Rn

Sr > Rb

Zn > Ga

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8 months ago

Chemistry NCERT Solutions

Boiling point of a 2% aqueous solution of a non-volatile solute A is equal to the boiling point of 8% aqueous of non-volatile solute B. The relation between molecular weights of A and B is

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alok kumar singh

Contributor-Level 10

For A : 100 gm solution 2 gm solute A

$∴ M o l a l i t y = \frac{2 / M_{A}}{0.098}$

For B : 100 gm solution 8 gm solute B

$∴ M o l a l i t y = \frac{8 / M_{B}}{0.092}$

$\frac{1}{4.261} = \frac{M_{A}}{M_{B}}$

$∴ M_{B} = 4.261 * M_{A}$

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8 months ago

Chemistry Class 12th

Given below are two statements. One is labeled as Assertion A and the other is labeled as Reason R.

Assertion A: Activated charcoal adsorbs SO₂ more efficiency than CH₄.

Reason R: Gases with lower critical temperature are readily adsorbed by activated charcoal.

In the light of the above statements, choose the correct answer from the options given below:

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alok kumar singh

Contributor-Level 10

SO₂ is absorbed to a greater extent then CH₄ on activated charcoal under same Gases with higher critical temperature are readily absorbed by activated charcoal.

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Chemistry Structure of Atom

Given below are two statements. One is labeled as Assertion A and the other is labeled as Reason R.

Assertion A: Energy of 2s orbital of hydrogen atom is greater that that of 2s orbital of lithium.

Reason R: Energies of the orbitals in the same subshell decrease with increase in the atomic.

In the light of the above statements, choose the correct answer from the options given below:

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alok kumar singh

Contributor-Level 10

Energy of orbitals in same subshell decrease on increasing the atomic number.

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8 months ago

Chemistry Class 12th

Given below are two statements.

Statement I: O₂, Cu²⁺, and Fe³⁺ are weakly attracted by magnetic field and are magnetized in the same direction as magnetic field.

Statement II: NaCl and H₂O are weakly magnetized in opposite direction to magnetic field.

In the light of the above statements, choose the most appropriate answer from the options given below.

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alok kumar singh

Contributor-Level 10

$O_{2}, C u^{2 +} a n d F e^{3 +}$

are paramagnetic

$∴$ Weakly attracted by magnetic field

NaCl and H2O are diamagnetic

$∴$ Weakly repelled by magnetic field.

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8 months ago

Chemistry Class 12th

250g solution of D-glucose in water contains 10.8% of carbon by weight. The molality of the solution is nearest to

(Given : Atomic weights are, H, 1u ; C, 12u ; O, 16u)

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alok kumar singh

Contributor-Level 10

$C_{6} H_{12} O_{6} \to G l u c o s e$

$\frac{M a s s o f C}{m a s s o f g l u c o s e} = \frac{72}{180}$

% of C = 10.8 = $\frac{M a s s o f C}{m a s s o f s o l u t i o n} * 100$

$\frac{10.8 * 250}{100} m a s s o f C$

$∴ M o l a r i t y = \frac{0.375}{0.1825} = 2.055 = 2.06$

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8 months ago

Chemistry Bond Parameters

Explain why the bond angle in ${N H}_{3}$ is larger than in ${P H}_{3}$ ?

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Himanshi Singh

Beginner-Level 5

The reason why bond angle is larger in ${N H}_{3}$ than ${P H}_{3}$ are given below.

In ${N H}_{3}$ , there is one lone pair on the nitrogen atom increases repulsion, while the lone pair on phosphorus is in a higher energy orbital and causes less repulsion.
Nitrogen is a small and electronegative atom whereas phosphorus is larger and less electronegative than nitrogen.
In ${P H}_{3}$ , the bonding orbitals are nearly pure p-orbitals, which are less directionals–p hybridization, on the other hand, the bond pairs remain fairly directed, leading to a larger bond angle.

Hence, the bond angle in ${N H}_{3}$ is about 107° ( less than the ideal tetrahedral 109.5°) due to lone pair pres

...more

The reason why bond angle is larger in ${N H}_{3}$ than ${P H}_{3}$ are given below.

In ${N H}_{3}$ , there is one lone pair on the nitrogen atom increases repulsion, while the lone pair on phosphorus is in a higher energy orbital and causes less repulsion.
Nitrogen is a small and electronegative atom whereas phosphorus is larger and less electronegative than nitrogen.
In ${P H}_{3}$ , the bonding orbitals are nearly pure p-orbitals, which are less directionals–p hybridization, on the other hand, the bond pairs remain fairly directed, leading to a larger bond angle.

Hence, the bond angle in ${N H}_{3}$ is about 107° ( less than the ideal tetrahedral 109.5°) due to lone pair presence and highly electronegative atom, and the bond angle in PH? ( 93.5°) is much smaller due to less repulsive lone pair, and less electronegative atom.

Hence, the bond angle in ${N H}_{3}$ (107°) is larger than in ${P H}_{3}$ (93.5°).

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