Chemistry

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9 months ago

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A
alok kumar singh

Contributor-Level 10

(a) Fully filled and half-filled orbitals have extra stability (that is, lower energy). Thus, p3, p6, d5, d10, f 7, f14 etc. configurations, which are either half-filled or filled, are more stable. Chromium and copper therefore adopt the d5 and d10 configuration.

New answer posted

9 months ago

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

It is a Wurtz reaction where alkane is formed.

New answer posted

9 months ago

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alok kumar singh

Contributor-Level 10

(c) The path of an electron in an atom can never be determined or known accurately. That is why there is only a probability of finding the electron at different points in an atom.

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

The structure of 2-methylbutane is 

2-methylbutane

 

Total number 

Total amount of monochlorinated

Product

% of monochlorinated product

9

9

41.7

2

7.6

35.2

1

5

23.1

 

New answer posted

9 months ago

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A
alok kumar singh

Contributor-Level 10

(a) Classical mechanics applies to the macro world and hence fails when it is applied to the micro world. In the micro world, quantum mechanics incorporates all the principles like the uncertainty principle, dual behaviour etc.

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9 months ago

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alok kumar singh

Contributor-Level 10

(d) Rainbow is a continuous spectrum.

Assertion is a wrong statement but Reason is a correct one. Rainbow is a continuous spectrum.

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

Electrophiles

Nucleophiles

(iii), (iv), (v)

(i), (ii), (vi), (vii), (viii)

New answer posted

9 months ago

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A
alok kumar singh

Contributor-Level 10

(a) For n = 4, No. of sub-shells = (l = 0, l = 1, l = 2, l = 3) = 4.

(b) Total number of orbitals which can be present = n2 = 42 = 16.
Each orbital can have an electron with ms = – 1/2. Total no. of electrons with m, = – 1/2 is 16.

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9 months ago

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

In presence of (Ph-CO-O)2it lead to CH3-CH2-CH2Br as the reaction undergo by free radical mechanism

However in absence of (Ph-CO-O)2 the reaction undergo by carbocation intermediate thus lead to give CH3-CHBr-CH3

New answer posted

9 months ago

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alok kumar singh

Contributor-Level 10

(a) P (Z=15) : [Ne]103s23p3  No. of unpaired electrons = 3
(b) Si (Z=14) : [Ne]103s23p2  No. of unpaired electrons = 2
(c) Cr (Z=24): [Ar]184s13d5  No. of unpaired electrons = 6
(d) Fe (Z=26): [Ar]184s23d6  No. of unpaired electrons = 4
(e) Kr (Z=36) : [Ar]184s23d104p6  No. of unpaired electrons = Nil.

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