Class 11th

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New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

Equation : 2x2 – (6 + k)x + 4 + 3k = 0

D < 0 => 6  4 2 < k < 6 + 4 2

Sum of integral values of K is 1+2+3+.+11 = 66

New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

Side of square = a

Radius of circle = r

Given : 4a + 2pr = 36

S = a2 + pr2

= ( π 2 4 + π ) r 2 9 π r + 8 1

d s d r = 0 r = 1 8 π + 4

New answer posted

3 months ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

0.0504 M NH4Cl of 5ml => millimole of N H 4 + = 0 . 0 5 0 4 * 5

0.0210 M NH3 of 2ml => millimole of NH3 = 0.0210 * 2

It is a basic buffer.

Total volume = 7ml

H e r e , K b = [ O H ] * [ N H 4 + ] [ N H 4 O H ]     

1 . 8 * 1 0 5 = [ O H ] * 0 . 0 5 0 4 * 5 0 . 0 2 1 0 * 2         

[ O H ] = 1 . 8 * 1 0 5 * 0 . 0 2 1 0 * 2 0 . 0 5 0 4 * 5 = 0 . 3 * 1 0 5 M  

[ O H ] = 3 * 1 0 6 M

x = 3   

Ans. = 3

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Δ H f 0 = ( + Δ H s u b 0 ) + ( + Δ H I E 0 ) + ( + 1 2 Δ H B D E 0 ) + ( Δ H E A 0 ) + ( Δ H L E 0 )

Δ H L E 0 = 8 9 . 2 + 4 1 9 + 1 2 1 . 5 3 4 8 . 6 + 4 3 6 . 7 k J m o l 1

Lattice energy = 717.8

New answer posted

3 months ago

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A
alok kumar singh

Contributor-Level 10

kindly go through the solution

 

New answer posted

3 months ago

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R
Raj Pandey

Contributor-Level 9

H 2 S ( a c i d ) + H 2 O B a s e ? H 3 O + + H S

H 2 O ( a c i d ) + N H 3 ( B a s e ) ? N H 4 O H

With H2S water acts like base and with NH3 it acts like acid.

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