Gravitation
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New answer posted
4 weeks agoContributor-Level 10
->R3 = (R + x)2 (R – x)
->R3 = (R2– x2) (R + x)
->x2 + Rx – R2 = 0
New answer posted
2 months agoContributor-Level 10

According to modified Ampere's law
For Loop
and
For Loop
and
Due to
New answer posted
2 months agoContributor-Level 10
For A satellite T1 = 1hour
for B satellite T2 = 8 hour
given R1 = 2 * 103 Km
Relative
rad/hour
x = 3

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