Laws of Motion

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New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
S
a year ago

For 2 kg block

T – 2g sin37 = 2a        . (i)

For 4 kg block

4g – 2T =  4 a 2

2g – T = a                    . (ii)

T = (2g – a)

2g – a – 2g ×  3 5  = 2a

3a = 2g ×  2 5

a = 4 g 1 5

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New answer posted•a year ago
New answer posted•a year ago
S
a year ago

fK = μmg cosq

= 0.1 × 5 0 × 3 2

= 2 . 5 3   N

 F1    = mg sinq + fK

= 25 + 2.5 3  

F2    = mg sinq – fK

= 25 – 2.5 

F1 – F2 = 5 3  N

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New answer posted•a year ago
S
a year ago

From F.B. Ds of

9 k g → 90 - T 1 = 9 a … . 1

6 k g → T 1 - T 2 = 6 a … . . ( 2 )

5 k g → T 2 - 50 = 5 a … . . 3

1 + 2 + ( 3 )

40 = 20 a ? a = 2 m / s 2

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New answer posted•a year ago
New answer posted•a year ago