Class 11th

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New answer posted

4 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

Sum of all elements of AB=2  [Sum of natural number upto 100 which are neither divisible by 3 nor by 5]

=2 [100*10123 (33*342)5 (20*212)+15 (6*72)]

= 10100 – 3366 – 2100 + 630

= 5264

New answer posted

4 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

(sin10°.sin50°.sin70°). (sin10°.sin20°.sin40°)

= (14sin30°). [12sin10° (cos20°cos60°)]

=132 [sin30°sin10°sin10°]

164116sin10°

Clearly α=164

Hence 16 + a-1 = 80

New answer posted

4 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

  (4+x2)dy2x (x2+3y+4)dx=0

dydx= (6xx2+4)y+2x

e3ln (x2+4)=1 (x2+4)3

So

y (x2+4)3=2x (x2+4)3dx+c

y=12 (x2+4)+c (x2+4)3

When x = 0, y = 0 gives

c=132

So, for x = 2, y = 12

New answer posted

4 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

60f (x)dx=2*12 (2+5)*3=21

New answer posted

4 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

Let y = mx + c is the common tangent

soc=1m=±321+m2m2=13

so equation of common tangents will be

y=±13x±3

which intersects at Q (3, 0)

Major axis and minor axis of ellipse are 12 and 6. So eccentricity

e2=114=34

and length of latus rectum

=2b2a=3

Hence

le2=33/4=4

New answer posted

4 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

Boys (10)            Girls (5)

(3)                        (3)

B1 & B2 should not be selected together

Total number of ways

           

= (56 + 56) * 10 = 1120

New answer posted

4 months ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

x4? 3x3? 2x2+3x+1=0

? x=±1

and let, are roots of x2 – 3x – 1 = 0

? ? +? =3? ? =? 1

? 13+ (? 1)3+? 3+? 3

= 27 + 3 (3) = 36

New answer posted

4 months ago

0 Follower 8 Views

P
Payal Gupta

Contributor-Level 10

 f (x)=2cos1x+4cot1x3x22x+10x [1, 1]

f' (x)=21x241+x26x2<0x [1, 1]

So, f (x) is decreasing function and range of f (x) is

[f (1), f (1)],  which is  [π+5, 5π+9]

Now 4a – b = 4 ( + 5) (5 + 9) = 11 - π

New answer posted

4 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

? T b = i K b m

? T f = i K f m

? 4 4 = K b * 1 . 5 K f * 4 . 5

K b K f = 3

New answer posted

4 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Moles of N2O 2 . 2 4 4 = 1 2 0

Δ H = n C p Δ T = 1 2 0 * 1 0 0 ( 4 0 ) = 2 0 0 J

Δ U = q p + w

w = P e x t . Δ V

w = 1 ( 1 6 7 . 7 5 2 1 7 . 1 ) 1 0 0 0 * 1 0 1 . 3 J = + 5 J

Δ U = 2 0 0 + 5 = 1 9 5 J

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