Class 11th

V = $\frac{}{}\frac{}{}$ $\frac{nRT}{P}=\frac{0.90*0.0821*300}{18*32}*760=29.21\cong 29$

$BaC{l}_2+S{O}_3^{2-}\stackrel{}{\to }\underset{White}{BaS{O}_3}\downarrow \stackrel{dil.HCl}{\to }\underset{\begin{array}{l}burningsulphur\\ likesmell\end{array}}{S{O}_2\uparrow }$

Primary structure of protein in unaffected by physical or chemical changes.

Data is not sufficient but official answer is (D)

Moles of PCl₅ = 5 mol

Moles of Ar = 4 mol

Total no of moles = 9 moles

^{$P_{Total}=\frac{nRT}{V}=\frac{9*0.0821*610}{100}=4.5atm$}

^{$P_{PC{l}_5}=X_{PC{l}_5}*P_T=\frac{5}{9}*4.5=2.5atm$}

^{$P_{Ar}=X_{Ar}*P_T=\frac{4}{9}*4.5=2atm$}

$PC{l}_5\stackrel{}{?}PC{l}_3+C{l}_2$

2.5 00

2.5 PPP

$P_{Total}=2.5-P+P+P+P_{Ar}=6$

P = 1.5 atm

$K_P=\frac{1.5*1.5}{1}=2.25$

Species =CH4 ${}_{}^{}$ $N{H}_4^{+}$ $B{H}_4^{?}$ ${}_{}^{}$

Electrons =101010

For 2S, number of radial moles = $n-\mathcal{l}-1=2-0-1=1$ $$ and ${}^{}$ ${\Psi }^2\left(r\right)$ will always be positive

$$ $\therefore option\left(B\right)iscorrect?$  it has one radial node and it is positive.

$\frac{0.02858*0.112}{0.5702}=0.0561$

Pascal's Triangle is a triangular array of binomial coefficients where each number is the sum of the two numbers directly above it, and its rows provide the coefficients for binomial expansions according to the Binomial Theorem. This le man language for defition of the passcl triangle.

$\frac{24}{\pi }{\displaystyle \underset{0}{\overset{\sqrt[]{2}}{\int }}\frac{\left(2-x^2\right)}{\left(x^2+2\right)\sqrt[]{4+x^4}}dx}$

$\frac{24}{\pi }{\displaystyle \underset{0}{\overset{\sqrt[]{2}}{\int }}\frac{x^2\left(\frac{2}{x^2}-1\right)dx}{x\left(x+\frac{2}{x}\right)*x\sqrt[]{\frac{4}{x^2}+x^2}}}$

$x+\frac{2}{x}=t$

$dt=\left(1-\frac{2}{x^2}\right)dx$

$=-\frac{12}{\pi }\left[\frac{\pi }{4}-\frac{2\pi }{2*2}\right]=-\frac{12}{\pi }\left[-\frac{\pi }{4}\right]=3$