Class 11th

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New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

(b) Both the statements are correct but R is not the reason for A.

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5 months ago

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A
alok kumar singh

Contributor-Level 10

(a) Fully filled and half-filled orbitals have extra stability (that is, lower energy). Thus, p3, p6, d5, d10, f 7, f14 etc. configurations, which are either half-filled or filled, are more stable. Chromium and copper therefore adopt the d5 and d10 configuration.

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5 months ago

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P
Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

It is a Wurtz reaction where alkane is formed.

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5 months ago

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A
alok kumar singh

Contributor-Level 10

(c) The path of an electron in an atom can never be determined or known accurately. That is why there is only a probability of finding the electron at different points in an atom.

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

The structure of 2-methylbutane is 

2-methylbutane

 

Total number 

Total amount of monochlorinated

Product

% of monochlorinated product

9

9

41.7

2

7.6

35.2

1

5

23.1

 

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

(a) Classical mechanics applies to the macro world and hence fails when it is applied to the micro world. In the micro world, quantum mechanics incorporates all the principles like the uncertainty principle, dual behaviour etc.

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alok kumar singh

Contributor-Level 10

(d) Rainbow is a continuous spectrum.

Assertion is a wrong statement but Reason is a correct one. Rainbow is a continuous spectrum.

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P
Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

Electrophiles

Nucleophiles

(iii), (iv), (v)

(i), (ii), (vi), (vii), (viii)

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5 months ago

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A
alok kumar singh

Contributor-Level 10

(a) For n = 4, No. of sub-shells = (l = 0, l = 1, l = 2, l = 3) = 4.

(b) Total number of orbitals which can be present = n2 = 42 = 16.
Each orbital can have an electron with ms = – 1/2. Total no. of electrons with m, = – 1/2 is 16.

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5 months ago

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

In presence of (Ph-CO-O)2it lead to CH3-CH2-CH2Br as the reaction undergo by free radical mechanism

However in absence of (Ph-CO-O)2 the reaction undergo by carbocation intermediate thus lead to give CH3-CHBr-CH3

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