Class 11th

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New answer posted

5 months ago

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Payal Gupta

Contributor-Level 10

This is a matching answer type question as classified in NCERT Exemplar

(i) → (d); (ii) → (a); (iii) → (b) : (iv) → (c)

New answer posted

5 months ago

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P
Payal Gupta

Contributor-Level 10

This is a matching answer type question as classified in NCERT Exemplar

(i) → (d); (ii) → (c); (iii) → (b) : (iv) → (a)

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

The correct option is B °
The balanced equation for the combustion of methane is:


CH4 (g)+2O2 (g)→CO2 (g)+2H2O (l)


Here,  Δng=1−3=−2


ΔH ° =ΔU ° +ΔngRT


ΔH ° =−393−2RT


∴ΔH ° °

New answer posted

5 months ago

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Payal Gupta

Contributor-Level 10

This is a matching answer type question as classified in NCERT Exemplar

(i) → (b); (ii) → (c); (iii) → (a)

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

option (iii)

Standard enthalpy of combustion is defined as the enthalpy change per mole (or per unit amount) of a substance when it undergoes combustion and all the reactants and products being in their standard states at the specified temperature.

New answer posted

5 months ago

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Payal Gupta

Contributor-Level 10

This is a matching answer type question as classified in NCERT Exemplar

(i) → (d); (ii) → (a); (iii) → (e) : (iv) → (c) : (v) → (b)

New answer posted

5 months ago

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(ii) & (iii)   

New answer posted

5 months ago

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(i) & (iii)

The structures that follow the (4n+2) Huckle rule of aromaticity is considered to be aromatic

New answer posted

5 months ago

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(i) & (iii)

The +I effect of the -OCH3 group stabilizes the carbocation.

The two resonating structure of CH2=CH-CH2CH2-CH=CH2 makes it more stable

New answer posted

5 months ago

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(i) & (iii) The nitro group strongly deactivate the ring due to the -R effect and -I effect

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