Class 11th

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Payal Gupta

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34. For diatomic molecules e.g. H2, O2, Cl2 etc. both energies are equal.

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Payal Gupta

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33.  (c) JK mol-1

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Payal Gupta

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3.  (ii) zero

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Payal Gupta

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2.  (iii) q = 0

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Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

The molar mass of the compound = 3.38 x 22400/896 =831gmol-1

Element

Percentage

At.mass

Relative ratio

the simplest ratio

C

87.8%

12

7.31

3

H

12.19%

1

12.19

5

Thus the empirical formula of the compound is C3H5

Molecular formula =n x empirical formula = 831/41 x C3H5 = C6H10

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Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

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Payal Gupta

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32. (c) Heat of combustion

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Payal Gupta

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31. (c) Volume and pressure respectively

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Payal Gupta

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30. (a) Macroscopic system only

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