Class 11th

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10 months ago

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Payal Gupta

Contributor-Level 10

44. Given, n (S) = 21

n (T) = 32

n (S T) = 11.

Using, n (S T) = n (S) + n (T) n (S T)

= 21 + 32 11

= 42.

New answer posted

10 months ago

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Payal Gupta

Contributor-Level 10

43. Let H and E be set if people who speak Hindi and English respectively. there,

n (H) = 250, people speak Hindi n (E) = 200, people speak English

n (H E) = 400, people speaks either Hindi or English

So, n (H E) = n (H) + n (E) n (H E)

= 250 + 200 400

= 50

So, 50 people can speak both Hindi and English.

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10 months ago

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Payal Gupta

Contributor-Level 10

42. Given, n (X Y) = 18.

n (X) = 8.n (Y) = 15.n (X Y) =?

Using n (X Y) = n (X) + n (Y) n (X Y)

= 8 + 15 18.

= 5.

New answer posted

10 months ago

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P
Payal Gupta

Contributor-Level 10

41. Given, n (X)= 17

n (Y) = 23

n (X Y)= 38.

So, n (X  Y) = n (X) + n (Y) n (X Y)

n (X Y) = n (X) + n (Y) n (X Y)

= 17 + 23 38.

= 2

New answer posted

10 months ago

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P
Payal Gupta

Contributor-Level 10

40.  (i) A' = U

(ii) ? ∩ A = U ∩ A = A.

(iii) A ∩ A'?  .

(iv) U' ∩ A = ?  ∩ A = ?  .

New answer posted

10 months ago

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Payal Gupta

Contributor-Level 10

39. A' = U – A

= Set of all triangle in a plane - Set of all triangle with at least the angle different from 60°.

= Set of all triangle with each angle 60°.

A? = set of all equilateral triangle.

New answer posted

10 months ago

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P
Payal Gupta

Contributor-Level 10

38. (i) (A B)' = U – (A B)

(ii) A' ∩ B' = (AU B)' = U – (AU B)

(iii) (A ∩ B)' = U – (A ∩ B)
(iv) A' U B' = (A ∩ B)' = U – (A ∩ B)'.

New answer posted

10 months ago

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Payal Gupta

Contributor-Level 10

37. (i) L.H.S = (A B)' = U – (A B)

= {1,2,3,4,5,6,7,8,9} – [ {2,4,6,8) {2,3,5,7}]

= {1,2,3,4,5,6,7,8,9} – {2,3,4,5,6,7,8}

= {1,9}

R.H.S. = A' ∩ B' = [U – A] ∩ [U B]

[ {1, 2, 3, 4, 5, 6, 7, 8, 9} {2, 4, 6, 8}] ∩  [ {1, 2, 3, 4, 5, 6, 7, 8, 9} {2, 3, 5, 7}]

= {1,3,5,7,9} ∩ {1,4,6,8,9}

= {1,9}

? L.H.S. = R.H.S.

(A B) = A ∩ B.

 

(ii) L.H.S. = (A ∩ B)' = U – (A ∩ B)

= {1,2,3,4,5,6,7,8,9} – [ {2,4,6,8} ∩ {2,3,5,7}]

= {1,2,3,4,5,6,7,8,9} – {2}

= {1,3,4,5,6,7,8,9}

R.H.S. = A' B'

= [U – A] [U – B]

= [ {1,2,3,4,5,6,7,8,9} – {2,4,6,8}] [ {1,2,3,4,5,6,7,8,9} – {2,3,5,7}]

= {1,3,5,7,9} {1,4,6,8,9}

= {1,3,4,5,6,7,8,9}

? L.H.S. = R.H.S.

(A ∩ B)' = A' B'.

New answer posted

10 months ago

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Payal Gupta

Contributor-Level 10

3. (i) {x : x is an odd natural number}

(ii) {x : x is an even natural number}

(iii) {x : x is not a multiple of 3}

(iv) {x : x is a positive composite number and x = 1}

(v) {x : x is a natural number not divisible by 3 and 5}.

(vi) {x : x is not a perfect square}

(vii) {x : x is not a perfect cube}

(viii) We have, x + 5 = 8.

x = 8 – 5 = 3

x = 3

? {x : x ≠ 3, x? N}

(ix )We have,

2x + 5 = 9

2x = 9 – 5

2x = 4

x = 2

? {x : x? N and x ≠ 2}

(x) {x : x < 7} = {1,2,3,4,5,6}

(xi) We have,

2x + 1 >10

2x >10 – 1

x > 92

?   {x:xx<92} = {1,2,3,4}

New answer posted

10 months ago

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P
Payal Gupta

Contributor-Level 10

35. (i) A' = U – A = {a, b, c, d, e, f, g, h} – {a, b, c}

= {d, e, f, g, h}

(ii) B' = U – B = {a, b, c, d, e, f, g, h} – {d, e, f, g}

= {a, b, c, h}.

(iii) C' = U – C = {a, b, c, d, e, f, g, h} – {a, c, e, g}.

= {b, d, f, h}

(iv) D' = U – D = {a, b, c, d, e, f, g, h} – {f, g, h, a}

= {b, c, d, e}

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