Class 12th

Contributor-Level 9

C = 10^-6 f

f = 0.5 * 10³ = 500

$z = \sqrt[]{x_{R}^{2} + {(x_{L} - x_{C})}^{2}}$

for minimum impedance :

x_L = x_C

$\Rightarrow ω^{2} = \frac{1}{L C}$

$\Rightarrow L = \frac{1}{π^{2}} = \frac{1}{10} * 1000 = 100 m H$

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6 months ago

In Friedel-Crafts alkylation of aniline, one gets

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Class 12th Physics Moving Charges and Magnetism

Contributor-Level 10

Aniline show acid-base reaction with AlCl₃

aniline is a Lewis base while AlCl₃ acts as lewis acid.

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Class 12th Physics

(if p = $\sqrt[]{10}$ )

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6 months ago

A singly ionized magnesium atom (A = 24) ion is accelerated to kinetic energy 5 ke V, and is projected perpendicularly into a magnetic field B of the magnitude 0.5 T. The radius of path formed will be ________cm.

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Contributor-Level 9

$r = \frac{m v}{q B} = \frac{\sqrt[]{2 k m}}{q B}$

$\frac{\sqrt[]{2 * 5 * 1 0^{3} * 1.6 * 1 0^{- 19} * 24 * 1.66 * 1 0^{- 27}}}{1.6 * 1 0^{- 19} * \frac{1}{2}}$

= 9.975 * 10^-2 cm

= 9.975 cm

$r \approx 10$ cm

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6 months ago

Two isomers (A) and (B) with molar mass 184 g/mol and elemental composition C, 52.2%; H. 4.9% and Br 42.9% gave benzoic acid and p-bromobenzoic acid respectively on oxidation with KMnO₄. Isomer 'A' is optically active and gives a pale yellow precipitate when warmed with alcoholic AgNO₃. Isomer 'A' and 'B' are respectively

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Contributor-Level 10

With AlCl₃, alkyl halide will form cabocation which will show rearrangement.

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6 months ago

Kindly consider the following

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Class 12th Physics Alternating Current

Contributor-Level 10

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An AC source is connected to an inductance of 100 mH, a capacitance of 100 $μ F$ and a resistance of 120 $Ω$ as shown in figure. The time in which the resistance having a thermal capacity 2 J/°C will get heated by 16°C is________ s.

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Contributor-Level 9

$x_{R} = 120 Ω$

$x_{L} = ω L = 100 * 100 * 1 0^{- 3} 10 Ω$

$x_{C} = \frac{1}{ω c} = \frac{1}{100 * 100 * 1 0^{- 6}} = 100 Ω$

$z = \sqrt[]{12 0^{2} + {(100 - 10)}^{2}} = \sqrt[]{12 0^{2} + 9 0^{2}}$

= 150 $Ω$

$\Rightarrow 32 = \frac{160}{75} * t \Rightarrow t = \frac{32 * 75}{160} = 15$

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6 months ago

Class 12th Physics

Current measured by the ammeter (A) in the reported circuit when no current flows through $10 Ω$ resistance, will be A.

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Class 12th Physics Current Electricity

Contributor-Level 9

Using whetstone

$\frac{R}{3} = \frac{4}{6} \Rightarrow R = 2 Ω$

$R_{e q u} = \frac{54}{15} Ω$

$i = \frac{36}{\frac{54}{15}} = 10 A$

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6 months ago

A meter bridge setup is shown in the figure. It is used to determine an unknown resistance R using a given resistor of 15 $Ω$ . The galvanometer (G) shows null deflection when tapping key is at 43cm mark from end A. If the end correction for end A is 2cm. Then the determined value of R will be ________ $Ω$ .

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Contributor-Level 9

At null point:

$\frac{15}{43 + 2} = \frac{R}{100 - 43}$

$\Rightarrow R = 19 Ω$

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6 months ago

Sulphur dioxide is one of the components of polluted air. SO₂ is also a major contributor to acid rain. The correct and complete reaction to represent acid rain caused by SO₂ is

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