Class 12th
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New answer posted
11 months agoBeginner-Level 5
students can check the table for the principal values for all ITFs below;
| Function | Principal Value Range (in radians) |
|---|---|
| sin? ¹x | –? /2 to? /2 |
| cos? ¹x | 0 to? |
| tan? ¹x | –? /2 to? /2 |
| cot? ¹x | 0 to? |
| sec? ¹x | 0 to? (except? /2) |
| cosec? ¹x | –? /2 to? /2 (except 0) |
New answer posted
11 months agoBeginner-Level 5
To understand this, Assume you have a bucket that has infinite number of apples and if your mother asks "give me the apple". How will you figure out which one is "The Apple", she is asking for.
Similarly any inversre trigonometric functions behaves like a Many-one Function; which means,
For Example can have many solutions, we need to fix one solutions which can be used as standerd value for the function.
- A standerd value (Angles) of any inverse trigonometric value lies between a fiexed range is known as principal value.
For Ex; The value of will always lie between –? /2 to? /2.
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11 months agoNew answer posted
11 months agoContributor-Level 10
7.33
Xe and F2 combine under different conditions to produce XeF2, XeF4, XeF6 as follows:
Ratio | Temperature & Pressure Condition | Reaction |
Excess | at {673K,1bar} | Xe (g) + F2 (g) → XeF2 (s) |
1:5 ratio | at {873K,7bar} | Xe (g) + 2F2 (g) → XeF4 (s) |
1:20 ratio | at {573K,60-70bar} | Xe (g) + 3F2 (g) → XeF6 (s) |
New answer posted
11 months agoContributor-Level 10
7.66
4NaCl + MnO2 + 4H2SO4 MnCl2 + 4NaHSO4 + 2H2O + Cl2
Manganese (IV) oxide reacts with sodium chloride and sulfuric acid to produce manganese (II) chloride, chlorine, sodium bisulfate and water.
This reaction takes place at a temperature near 100°C.
Cl2 + NaI 2NaCl + I2
Chlorine reacts with sodium iodide to produce sodium chloride and iodine. Chlorine - diluted solution.
Sodium iodide - cold solution.
New answer posted
11 months agoContributor-Level 10
7.64
Neil Bartlett first performed an experiment in which reaction between oxygen and PtF6 was carried out which lead to the formation of a red coloured compound O2 + [PtF6 ]-.
He observed that the first ionization energy of Oxygen and Xenon is almost same (~1170 kJ/mol). So, he tried to react Xe and PtF6 in which he was successful to obtain a red coloured compound Xe+ [PtF6]-.
New answer posted
11 months agoContributor-Level 10
7.63
By Deacon's process Cl2 can be prepared from HCl in presence of CuCl2
4HCl + O2? 2Cl2 + 2H2O
Cl2 on treating with water gives HCl
Cl2 + H2O? HCl + HOCl
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