P Block Elements
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HClO4 is the most acidic compound.
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When copper is reacted with dilute HNO3, the gaseous product(s) obtained is/are
When copper is reacted with dilute HNO3, the gaseous product(s) obtained is/are
Group number = 11 (Atomic number = 111)
Upvote It is because of inability of ns2 electrons of the valence shell to participate in bonding that
It is because of inability of ns2 electrons of the valence shell to participate in bonding that
Heavier element of p block do not from pπ− pπ bonds as their atomic orbital are so large and diffius that they cannot have effecitve overlapping.
Upvote Identify the metal whose hydroxide reacts with both acid as well as base.
Identify the metal whose hydroxide reacts with both acid as well as base.
The inertness of
Upvote Statement-I : Among 15th group hydrides reducing character decreases from NH3 to BiH3.
Statement-II : E2O3 and E2O5 are always basic.
[Where E is group 15 element]
Statement-I : Among 15th group hydrides reducing character decreases from NH3 to BiH3.
Statement-II : E2O3 and E2O5 are always basic.
[Where E is group 15 element]
Reducing character increases from NH3 to BiH3.
Group 15 oxides of type E2O3 and E2O5 are not always basic.
Upvote Choose the correct answer :
Statement 1 : S8 disproportionate into H2S2O3 and S2– in alkaline medium
Statement 2 : <!-- [if gte mso 9]><xml>
Choose the correct answer :
Statement 1 : S8 disproportionate into H2S2O3 and S2– in alkaline medium
Statement 2 : <!-- [if gte mso 9]><xml>
(2) Cl is in its the highest oxidation state (+7). It cannot be further oxidised
Upvote XeF2 : Hybrid orbital = s bond + L.P
= 2 + 3
= 5 = sp3d
Shape ->linear
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Hybridisation = sp3d2
Shape – square planar
Upvote Anionic species obtained on reaction of XeF2 with PF5 is
Anionic species obtained on reaction of XeF2 with PF5 is
XeF2 + PF5 ¾-> [XeF]+ [PF6]–
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