Class 12th

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New answer posted

2 months ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

f (x) = x? /20 - x? /12 + 5
f' (x) = x? /4 - x³/3 = x³ (x/4 - 1/3)
Local maxima at 0, Local minima at 4/3
f' (x) = x³ - x² = x² (x-1)
x = 1 point of inflection

New answer posted

2 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

dy/√ (1-y²) = dx/x²
sin? ¹ (y) = -1/x + c ⇒ c = π/2
sin? ¹ (y) = -π/3 + π/2 = π/6
y = 1/2

New answer posted

2 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

a a ( | x | + | x 2 | ) d x = 2 2 , a > 2

a 0 ( 2 x + 2 ) d x + 0 2 ( x x + 2 ) d x + 2 a ( 2 x 2 ) d x = 2 2

2 a 2 + 2 = 2 0 a 2 = 9 a = 3

3 3 ( x + [ x ] ) d x = 3 3 ( 2 x { x } ) d x = 3 3 2 x d x + 6 0 1 x d x = 6 . x 2 2 | 0 1 = 3           

            

New answer posted

2 months ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

V 1 = k Q 3 3 R + k Q 2 2 R + k Q 1 R = 30

V 2 = k Q 3 3 R + k Q 2 2 R + k Q 1 2 R = 15

V 3 = k Q 3 3 R + k Q 2 3 R + k Q 1 3 R = 10

Eq. (1) &  (2) k Q 1 R = 30  

Eq. (2) &  (3) k Q 2 6 R + k Q 1 6 R = 5 k Q 2 R = - k Q 1 R + 30 = 0

By (3) k Q 3 R = 30 - k Q 2 R - k Q 1 R = 0

Potential of innermost shell (earthed) = k Q 1 ' R + k Q 2 2 R + k Q 3 3 R = 0

k Q 1 ' R = 0 Q 1 ' = 0

New answer posted

2 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

P = [ 3 1 2 2 0 α 3 5 0 ] a n d Q = [ q i j ] P Q = k l 3           

q 2 3 = k 8 a n d | Q | = k 2 2            

P Q = k l 3 P 1 = Q k = ( 3 1 2 2 0 α 3 5 0 ) 1           

| p | | Q | = ( k l 3 ) 8 . k 2 2 = k 3

k 0 k = 4

α 2 + k 2 = 1 + 1 6 = 1 7 .          

          

New answer posted

2 months ago

0 Follower 2 Views

V
Vikash Kumar Vishwakarma

Contributor-Level 7

DNA and RNA both are the types of nucleic acids.

  • DNA (Deoxyribonucleic acid) store the genetic  information.

  • RNA (Ribonucleic acid) helps in protein synthesis. It carry and translates the genetic codes.

New answer posted

2 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

  c = α a + β b . . . . . ( i )

  a . c = 7 b . c = 0         

a = i ^ + j ^ + k ^ | a | = 3           

b = 2 i ^ + k ^ | b | = 5 a . b = 2 + 1 = 1           

From   ( i ) a . c = α | a | 2 β

3 α β = 7 . . . . . . . . . . ( i i )           

b ¯ . c ¯ = α b ¯ . a ¯ + β | b | 2 α + 5 β = 0 . . . . . . . ( i i i )           

Solving α = 5 2 a n d β = 1 2

2|a+b+c|2=75            

 

New answer posted

2 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

f (x) = λ (x-2)²
⇒ 12 = λ (2)² ⇒ λ = 3
f (x) = 3 (x-2)² f (6) = 3 * 4² = 48

New answer posted

2 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

∫ (from 0 to 3) (x-1) (x-2) (x-3) dx = ∫ (from 0 to 3) (x³ - 6x² + 11x - 6) dx


A = ∫ (from 0 to 1) (x³ - 6x² + 11x - 6) dx - ∫ (from 1 to 2) (x³ - 6x² + 11x - 6) dx + ∫ (from 2 to 3) (x³ - 6x² + 11x - 6) dx
A = 11/4

New answer posted

2 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Let P (B1) = a      P (B2) = b            P (B3) = c

Given a (1 – b) (1 – c) = a . (i)

b (1 – a) (1 – c) = b              . (ii)

c (1 – b) (1 – a) =  γ             . (iii)

(1 – a) (1 – b) (1 – c) = p     . (iv)

( α 2 β ) p = α β  

->a – ab – 2b + 2ab = ab Þ a = 2b . (v)

Again ( β 3 γ ) p = 2 β γ  

-> b – bc – 3c + 3bc = 2bc Þ b = 3c   . (vi)

P ( B 1 ) P ( B 3 ) = a c = 2 b b / 3 = 6        

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