Class 12th

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New answer posted

6 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

V_common = (C? V? + C? V? )/ (C? + C? )? 2 = (3? F)*12)/ (3? F)+ (3? F)*K)? 2 = 12/ (K+1)? K = 5

New answer posted

6 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

β = (λD/d) ⇒ Δβ = (ΔDλ/d) ⇒ 4 * 10? = (λ/10? ³) * 8 * 10? ² ⇒ λ = 5 * 10? m = 500 nm

New answer posted

6 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

Velocity of bird = v
Velocity w.r.t. observer in water = (4/3)v; 12 = 4 + (3/4)v ⇒ v = 6 cm/s

New answer posted

6 months ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

s? = -? + k? ∴ s? = (-? +k? )/√2

New answer posted

6 months ago

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A
alok kumar singh

Contributor-Level 10

  7 * D λ d = ( μ 1 μ 2 ) t . D d  

t = 9.1    μ m

New answer posted

6 months ago

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V
Vishal Baghel

Contributor-Level 10

Energy of products = 939 + 940 = 1879
ΔE + E_reactions – E_productor = 1877 – 1879 = -2MeV.
Hence it must capture a γ - ray photon of energy 2MeV.

New answer posted

6 months ago

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V
Vishal Baghel

Contributor-Level 10

X? = X? ⇒ ωL = R ⇒ 2 * 3.14 * 50 * L = 20 ⇒ L = 63.7mH

New answer posted

6 months ago

0 Follower 54 Views

A
alok kumar singh

Contributor-Level 10

  5 * 1 0 3 I 1 = 6 0

I 1 = 6 0 5 * 1 0 3 = 1 2 m A                  

Potential difference across

1 0 k Ω = 2 4 0 6 0 = 1 8 0 V            

I 2 = I 3 I 1 = 6 m A            

New answer posted

6 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Photon energy  = h c λ = 1240 e V . n m 500 n m = 2.48 e V = 2.48 * 1.6 * 10 - 19 J = 4 * 10 - 19 J

No. of photons emitted per sec =   power     photon Energy   = 100 4 * 10 - 19 s - 1 = 2.5 * 10 20 s - 1

New answer posted

6 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

n (7800) = (n + 1) 5200

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