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9 months ago

Class 12th Biomolecules

The number of ketonic >C=O groups present in a tripeptide gly-ser-val are ____.

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Raj Pandey

Contributor-Level 9

The number of >C = 0 groups in tripeptide is 0 .

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9 months ago

Class 12th Maths

The value of 'a' for which the straight line 4x – 3y + 4z – 2 = 0 = 3x – 2y + z – 5 is parallel to the plane 2x – y + az – 7 = 0, is:

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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9 months ago

Class 12th Chemistry Electrochemistry

A weakly alkaline solution of permanganate is electrolysed for 50 minutes using 2A current. The amount of oxide of manganese obtained. (Given : Atomic mass Mn = 55 amu and O = 16 amu)

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Raj Pandey

Contributor-Level 9

Charge (q) $= i t = 2 * 50 * 60 = 6000 C$

$\Rightarrow 6000 C = (\frac{6000}{96500} F)$

${M n O}_{4}^{-} + 3 e^{(-)} + 2 H_{2} O \overset{weakly alkaline medium}{?} {M n O}_{2} + 4 {O H}^{-}$

Mass of ${M n O}_{2}$ deposited $= \frac{1}{3} * \frac{6000}{96500} * 87 = 1.8$

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Class 12th Chemistry Solutions

1.34% solution of KNO? is isotonic with 4.77% solution of glucose. Find the percent of dissociation of KNO?. (Given : Atomic mass K = 39.1 amu, N = 14 amu and O = 16 amu)

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Raj Pandey

Contributor-Level 9

$\to$ $π_{{K N O}_{3}} = π_{glucose.}$

$(i C R T)_{{K N O}_{3}} = (C R T)_{glucose}$

$\frac{}{} \frac{}{}$ $\frac{i * 1.34}{101.1} * R T = \frac{4.77}{180} * R * T$

$i = \frac{4.77}{180} * \frac{101.1}{1.34} = 2$

Hence, extent of dissociation is $100 %$

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9 months ago

Class 12th Determinants

If Δ =
| 1 3cosθ 1 |
| sinθ 1 sinθ |
| 1 3cosθ 1 |
, then the maximum value of Δ is:

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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9 months ago

Class 12th Chemistry

The major product of the following reaction is:
(3-methylpentan-2-ol reacts with conc. H?SO? and Heat)

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Raj Pandey

Contributor-Level 9

Kindly consider the following Image

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9 months ago

Class 12th Chemistry

Match the following drugs with their therapeutic action:
(I) Cimetidine structure
(II) Iproniazid structure
(III) Penicillin structure (general)
(IV) Terfenadine structure

(a) Antidepressant
(b) Antibiotic
(c) Antihistamine
(d) Antacid
(e) Analgesic

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Raj Pandey

Contributor-Level 9

(1) Cimetidine $E = P h - C H - {C H}_{3}$ $_{}$ Antacid

(2) Iproniazid ${C H}_{3}$ $_{}$ Antidepressant

(3) Penicillin $\to$ Antibiotic

(4) Terfenadine $\to$ Antihistamines

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9 months ago

Class 12th Chemistry

Three isomers A, B and C (mol. formula C?H?O?) gives the following results:
B or C →Decarboxylation→ D(C?H?)
A →Decarboxylation→ E(an isomer of D)
Both D and E are non-resolvable.
D or E →H?/KMnO?→ Benzoic acid
B is more reactive than C towards decarboxylation reaction.
A, B, C respectively are:

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Raj Pandey

Contributor-Level 9

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New answer posted

9 months ago

Class 12th Chemistry Coordination Compounds

The d-electron configuration of [Fe(H?O)?(NO)]²? and K?[Cr(CN)?] respectively are:

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Raj Pandey

Contributor-Level 9

In ${[F e ? {(H_{2} O)}_{5} (N O)]}^{2 +}$

${F e}^{+ 1} (3 d^{7})$

In ${[{C r}^{+ 3} (C N)_{6}]}^{3 -}$

${C r}^{+ 3} (3 d^{3})$

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9 months ago

Class 12th Chemistry

Complex A has a composition of H?O?Cl?Cr. It has green colour. A 0.2M solution of complex when treated with excess of AgNO? gave 57.45gm of white precipitate. The formula of the complex would be: [Given: at mass Cr = 52amu, Cl = 35.5amu, Ag = 107.8amu ]

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Raj Pandey

Contributor-Level 9

0.2 mole gives $\to 0.4$ mole of $A g C l$ (moles of $A g C l = \frac{57.45}{143} = 0.4$ $\frac{}{}$ )

1 mole complex gives $\to \frac{0.4}{0.2} = 2$ $\frac{}{}$ moles $A g C l$

The correct answer should be $2^{nd}$ $^{}$ option.

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