Class 12th
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New answer posted
a year agoContributor-Level 10
de-Broglie wavelength
λ = h/mv = h / √ (3kT/m * m) = h / √ (3mkT)
λ = (6.63 * 10? ³? ) / √ (3 * 4.64 * 10? ²? * 1.38 * 10? ²³ * 400)
λ = (6.63 / 2.77) * 10? ¹¹ = 2.39 * 10? ¹¹ m ≈ 0.24Å
New answer posted
a year agoContributor-Level 9
Eext > 1.1 V, cell reaction is reversed
i.e. Cu → Cu²? anode
Zn²? + 2e? → Zn cathode
New answer posted
a year agoContributor-Level 10
From aerie's law x = c/r
I = xH
I? = x? H?
I? = x? H?
I? /I? = x? H? /x? H?
I? /I? = T? H? /T? H? = (4 x 0.3)/ (24 x 0.4) = 1/8
I? = T? /8 = 6/8 = 0.75
New answer posted
a year agoContributor-Level 10
P = (μ – 1) (1/R – 1/ (-R)
P = 2 (μ – 1)/R
1.5P = (μ – 1)/R') * 1.5 = 1/2R'
R' = R/3
New answer posted
a year ago
New answer posted
a year agoContributor-Level 10
i = V/r {1 - e? /? }
i? = V/r
U = ½Li²
½ L (V²/r²) {1 - e? /? } = (1/n) x (LV²/2r²)
1 - e? /? = 1/√n ; e? /? = 1 - 1/√n = (√n - 1)/√n
e? /? = √n/ (√n - 1) ; rt/L = ln (√n/ (√n - 1)
T = L/r ln (√n/ (√n - 1)
New answer posted
a year agoContributor-Level 10
In Ohm's law experiment, ammeter is used in series because in series same current will flow through it. But voltmeter is used in parallel to resistor to measure the potential difference across it.
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