Class 12th
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New answer posted
10 months agoContributor-Level 9
A - B has the lowest potential energy and it means it has stronger bond.
New answer posted
10 months agoContributor-Level 10
Binding energy = (50M? + 70M? – Msn)C²
= (50.3915 + 70.6069 – 119.902199)U²
= (1.0962U)C²
= 931 * 1.0962MeV
Binding energy per neucleon
= (931 x 1.0962)/120 MeV
= 8.5MeV
New answer posted
10 months agoContributor-Level 10
By conservation of energy
(K.E. + P.E.)? = (K.E. + P.E.)?
0 + (1/ (4πε? a³) * 2P * P = 2 * (1/2)mv² + 0
v = √ (p² / (2πε? ma³) = (P/a) * √ (1 / (2πε? ma)
New answer posted
10 months agoContributor-Level 10
Sol. eVslop = hc/λ - φ
Slope of curve
tan θ = hc/e = constant
as intensity of incident radiation is increased, there will be no effect on graph
New answer posted
10 months agoContributor-Level 10
Q? = CV?
U? = ½CV? ²
q? = (q? C)/ (C + C/2) = 2q? /3
q? = (q? (C/2)/ (C + C/2) = q? /3; Uf = q? ²/2C + q? ²/2 (C/2)
= (4q? ²/9x2C) + (q? ²/9C)
= (6q? ²/18C) = q? ²/3C = CV? ²/3
Energy loss in the process = U? – Uf
= ½CV? ² - CV? ²/3
= CV? ²/6
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