Class 12th

Each of the element in group III  to VIIIB  can show the maximum oxidation state equal to its group number.

Mn is in group seven shows a maximum oxidation state of +7 in KMnO₄

Please find the solution below:

In the metallurgy of aluminium, purified Al₂O₃ is mixed with Na₃AIF₆ or CaF₂ which lowers the melting point of the mixture and brings conductivity.

Sucrose is non-reducing sugar. It does not reduce Fehling solution.

Heavier element of p block do not from pπ− pπ bonds as their atomic orbital are so large and diffius that they cannot have effecitve overlapping.

Acyl chloride is hydrogenated over catalyst, palladium or barium sulphate. This reaction is called Rosenmund reaction.

The inertness of ? subshell electrons towards bond formation is known as inert pair effect. This effect increases down the group thus, for Sn,  oxidation state is more stable, whereas, for Pb,  oxidation state is more stable, i.e.,  is reducing while  is oxidising.

Kindly go through the solution 

Charge on C₁ = CV

            Charge on C₂ = 4CV

When connected in parallel

$V_C=\frac{5V}{3}$  

$Q{\text{'}}_1=\frac{5}{3}CV$ $Q{\text{'}}_2=\frac{10}{3}CV$

$?$ $E=\frac{1}{2}C{V}^2$

$E\text{'}=\frac{25}{18}C{V}^2+\frac{25}{9}C{V}^2$  

$\frac{25}{6}C{V}^2=\frac{50E}{6}$

x = 50

$-0.85=\frac{-13.6}{n^2}$  

n = 4

Number of transitions = $\frac{4*3}{2}=6$