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Class 12th Chemistry

Positive Fehling solution test is given by

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alok kumar singh

Contributor-Level 10

Fehling solution test can be given by aldehyde except aromatic aldehyde

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Class 12th Chemistry Chemical Kinetics

Given $K_{n e t} = \frac{K_{1} K_{2}}{K_{3}}$ when $E_{a_{1}}$ =40 kJ/mol

$E_{a_{1}}$ =50 kJ/mol. = $E_{a_{1}}$ 60 kJ/mol

Calculate value of (E_a)_net in kJ/mol

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alok kumar singh

Contributor-Level 10

(E_a)_net = $E_{a_{1}}$ + $E_{a_{2}}$ – $E_{a_{3}}$

= 40 + 50 – 60

= 90 – 60

= 30kJ/mol

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Class 12th Chemistry Solutions

Calculate the molarity of a solution having density = 1.5g/mL %(w/w) of solute is 36% and molecular 36 g/mol

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alok kumar singh

Contributor-Level 10

Assume mass of solution

= 100g

Mass of solute = 36gm

Moles of solute = 1

Molarity= $\frac{1 * 1000}{(\frac{100}{1.5})} = \frac{1000}{100} * 1.5 = 15$

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Class 12th Ncert Solutions Chemistry Class 12th

What are the benefits of using Class 12 Chemistry Chapter 1 NCERT Solutions?

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Esha Garg

Beginner-Level 5

NCERT offers the foundation for every class 12 student. CBSE board exam questions are primarily based on the NCERT exercise, Examples and conceptual explanation.

There are various benefits of using NCERT Solutions.

Specially for CBSE Board students, these NCERT Solutions are the best resource to prepare for the boards.
These NCERT Solutions include step-wise descriptive answer approach that will help you write good answers.
These solutions also help you understand problem-solving and how to approach a specific type of conceptual or numerical problem.
If you are preparing for the JEE or NEEt exam, these solutions can be your first deci

...more

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Class 12th Chemistry

K₂Cr₂O₇ + H₂O₂ + H₂SO_{4
$\to_{c o n d i t i o n s}^{e t h e r c o l d}$} compound 'X' X is a chromium compound, what is the oxidation state of chromium in compound 'X'.

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alok kumar singh

Contributor-Level 10

K₂Cr₂O₇ + H₂O₂ + H₂SO₄-> + K₂SO₄ + H₂O compound 'X' is ->CrO₅

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Class 12th Chemistry Coordination Compounds

Match the following

	Column I (Complexes)		Column II (Metals)
A.	Vitamin B₁₂	(p)	Ti
B.	Wilkinson catalyst	(q)	Co
C.	Ziegler-Natta catalyst	(r)	Fe
D.	Haemoglobin	(s)	Rh

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alok kumar singh

Contributor-Level 10

A. Vitamin B₁₂– Co

B. Wilkinson catalyst –Rh ( [Rh (PPh₃)₃Cl])

C. Ziegler-Natta catalyst –Ti (TiCl₄ +Al (C₂H₅)₃)

D. Haemoglobin – Fe

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Class 12th Chemistry

Statement 1 :lonisation energy decreases in a period.

Statement 2 : In a period Z dominates over screening effect

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alok kumar singh

Contributor-Level 10

Ionisation enthalpy increases in a period. Z dominates over screening effect (s) in a period as Z_eff. increases.

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Class 12th Class 12-science

Why you should use Shiksha's NCERT Solutions for Chapter 1 Solutions Class 12 Chemistry?

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Satyendra Dhyani

Beginner-Level 5

Shiksha focuses on completely fulfilling the needs of CBSE class 12 board students. We provide NCERT Solutions for classes 11th and 12th in class for physics, chemistry and mathematics.

Here are the key reasons why you should use Shiksha's NCERT Solutions for the Solution Chapter:

Complete coverage of NCERT Exercise, including MCQs, very short, short and long answer type questions.
Step-by-step solutions according to the CBSE board exam needs.
Intext question and answer with a free downloadable PDF
complete study material for the chapter
- NCERT Chapter 1 Solutions Notes
- Solutions Quick Revision Notes
- Important Questions for Solution

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Class 12th Chemistry

Which of the following element(s) is/are confirmed by appearance of blood red colour with FeCl₃ in Lassaigne's test?

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alok kumar singh

Contributor-Level 10

Na+ C + N + S ®NaSCN

Fe³⁺ + SCN^– $\overset{}{\to}$ $\underset{B l o o d r e d}{{[F e (S C N)]}^{2 +}}$

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Class 12th Chemistry

Alkaline KMnO oxidises lodide to a particular product (A). Determine the oxidation state of lodine in compound (A).

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alok kumar singh

Contributor-Level 10

Potassium permanganate in alkaline medium oxidise lodide to lodate.

$2 M n O_{4}^{-} + H_{2} O + I^{Θ} \overset{}{\to} 2 M n O_{2} + 2 O H^{Θ} + I O_{3}^{Θ} (A)$

Compound A is . Therefore, oxidation state of 1is + 5.

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