Class 12th

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New answer posted

10 months ago

0 Follower 7 Views

R
Raj Pandey

Contributor-Level 9

P (CO? ) = K? X (CO? )
X (CO? ) = P (CO? )/K? = 0.835 / (1.67 * 10³) = 0.5 * 10? ³
X (CO? ) = n (CO? )/ (n (CO? ) + n (H? O) ≈ n (CO? )/n (H? O) (since n (CO? ) << n (H? O)
n (H? O) in 0.9L = 900g/18gmol? ¹ = 50 mol
n (CO? ) = X (CO? ) * n (H? O) = 0.5 * 10? ³ * 50 = 25 * 10? ³ moles = 25 mmol

New answer posted

10 months ago

0 Follower 26 Views

R
Raj Pandey

Contributor-Level 9

[Reactions showing reduction of various functional groups]
(1) Nitrile reduced to primary amine with H? /Ni.
(2) Nitrile and aldehyde reduced to primary amine and alcohol with LAH.
(3) Nitro group reduced to primary amine with Na/Hg, C? H? OH.
(4) Nitrile reduced to aldehyde with SnCl? /HCl.
Products of reaction 1, 2 and 3 are 1° amines, so react with Hinsberg's reagent to form sulphonamide. Product of (4) is an aldehyde, which does not react.

New answer posted

10 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution 

 

New answer posted

10 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

Cl?C=CCl? is not used for dry cleaning of clothes due to safety purpose.

New answer posted

10 months ago

0 Follower 36 Views

R
Raj Pandey

Contributor-Level 9

(a) Rate vs Time for zero order is a horizontal line (Rate = const.)
(b) t?/? vs Concentration for zero order is a straight line through the origin (t?/? ∝ [C?])
(c) Concentration vs Time for first order is an exponential decay (C? = C?e?)
(d) Concentration vs Time for a reaction is a decreasing curve, not a horizontal line.
(e) Rate vs Concentration for first order is a straight line through the origin (Rate = k[Conc.]¹)

New answer posted

10 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

ai+aj+ck,  i+k and ci+cj+bk are co-planar,
|a c; 1 0 1; c b| = 0
a (0-c) - a (b-c) + c (c-0) = 0
-ac - ab + AC + c² = 0
c² = ab
c = √ab

New answer posted

10 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

(x/m) = k (p)¹/? (1)
64 (x/m) = k (2p)¹/? (2)
From equation (1) and (2)
64 = 2¹/?
2? = 2¹/?
1/n = 6
n = 1/6
⇒ n = 0.167
= 16.7 * 10? ²

New answer posted

10 months ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

[Diagram of a micelle formed by sodium stearate in oil]
Spherical micelles forms and hydrocarbon part are water repelling and attracted by oily part.

New answer posted

10 months ago

0 Follower 11 Views

A
alok kumar singh

Contributor-Level 10

R? → R? -R? , R? → R? -R?
|sinx-cosx, cosx-sinx, 0; 0, sinx-cosx, cosx-sinx; cosx, sinx| = 0
(sinx-cosx)² |1, -1, 0; 0, 1, -1; cosx, sinx| = 0
(sinx-cosx)² (1 (sinx+cosx) + 1 (cosx) = 0
(sinx-cosx)² (sinx + 2cosx) = 0
sin x = cos x
tan x = 1 ⇒ x = π/4
or
sin x = -2cos x
tan x = -2
Not within given range.

New answer posted

10 months ago

0 Follower 11 Views

V
Vishal Baghel

Contributor-Level 10

? = CRT
2.42 * 10? ³ = ( (1.46/M_polymer) / 0.1 ) * 0.083 * 300
M_polymer = (1.46 * 0.083 * 300) / (2.42 * 10? ³ * 0.1)
= 14.96 * 10? gm = 15 * 10? gm

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