Class 12th
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New answer posted
10 months agoContributor-Level 9
Let L be the vertical distance between the centers of two adjacent balls.
Also, if the box can hold n sphere then (n – 1) L + 2r
≤ 9r [ the last ball height = 2r]
n ≤ 5.04
Since, n is a natural number.
n = 5
So, the box can hold maximum of 5 spheres.
New answer posted
10 months agoContributor-Level 9
9B + 3 + 5G + 4 = 200 9B + 5G = 193
The positive integer solutions are (B, G) = (2, 35) (7, 25) (12, 17) (17, 8)
Only one of the (B, G) gives G > B and 9B + 3 > 100, i.e. (B, G) = (12, 17)
17 * 5 = 85
New answer posted
10 months agoContributor-Level 10
(a):Let, s be the speed of stream.
So, 8 + s = 2 (8 – s)
s = 8/3 mph
New answer posted
10 months agoContributor-Level 9
9B + 3 + 5G + 4 = 200 9B + 5G = 193
The positive integer solutions are (B, G) = (2, 35) (7, 25) (12, 17) (17, 8)
Only one of the (B, G) gives G > B and 9B + 3 > 100, i.e. (B, G) = (12, 17)
17 – 12 = 5
New answer posted
10 months agoContributor-Level 10
(c) :As per the problem:
Average score of 20 candidate = 25 marks
Total score of 20 candidate = 500 marks
Let the score of the topper be x. Then,
500 – x = 437
x = 500 – 437 = 63 marks
New answer posted
10 months agoContributor-Level 9
9B + 3 + 5G + 4 = 200 9B + 5G = 193
The positive integer solutions are (B, G) = (2, 35) (7, 25) (12, 17) (17, 8)
Only one of the (B, G) gives G > B and 9B + 3 > 100, i.e. (B, G) = (12, 17)
12 * 9 – 17 * 5 = 23
New answer posted
10 months agoContributor-Level 10
f (3n) – f (3n– 3) = n
n = 1
f (3) – f (0) = 1
f (0) = 0
n = 2
f (3n) – f (3) = 2 + 3 + 4+…………….+ n
f (3n) = 1 + 2 + 3 +…………….+ n
=
f (1312) – f (3 * 311)
Hence, remainder = 8
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