Class 12th

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New answer posted

a year ago

0 Follower 17 Views

P
Payal Gupta

Contributor-Level 10

Let the radius of circle be 'r'

In D QPB

OP = 12 – r

PB = 6

QB = 12 + r

(12+r)2 = (12–r)2 + 62

r = ¾

Area of circle = pr2

= 22/7 * 3/4 * 3/4

= 9 9 5 6 s q     c m

New answer posted

a year ago

0 Follower 9 Views

A
alok kumar singh

Contributor-Level 10

According to Brewster's law, reflected rays are completely polarized and refracted rays are partially polarized.

 

New answer posted

a year ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

P1 + P2 + P3 = 59

P1 and P2 → minimize

Then P3 → minimum i.e. 47

P1

P2

P3

5

7

47

5

11

43

3

13

43

5

13

41

5

17

37

3

19

37

5

23

31

7

23

29

So, only possible value of P3 can take → 29, 31, 37, 41, 43, and 47

Total 6 values

New answer posted

a year ago

0 Follower 18 Views

A
alok kumar singh

Contributor-Level 10

Time period of Oscillation, T = 2 π I M B

⇒ 1 4 = 2 π 9 . 8 * 1 0 − 6 M * 0 . 0 4 9

⇒ 1 1 6 = 4 π 2 * 9 . 8 * 1 0 − 6 M * 4 9 * 1 0 − 3

⇒ M = 4 π 2 * 9 . 8 * 1 0 − 6 4 9 * 1 0 − 3 * 1 6

= 4 π 2 * 9 . 8 * 1 6 * 1 0 − 3 4 9

= 1 2 . 8 π 2 * 1 0 − 3 * 1 0 − 2 * 1 0 2

=1280π2*10−5Am2

New answer posted

a year ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

1x=115−6y

1x=y−9015y

x=15yy−90 ______equation 1

i.e. y = 90+y,

1≤ y1 ≤9

y1 is odd

Equation 1 becomes

x=15 (90+y1)y1

=15+90*15y1

y1 can take 1,3,5,9

y=91, 93, 95, 99

New answer posted

a year ago

0 Follower 5 Views

P
Payal Gupta

Contributor-Level 10

Sol1

20percent (0.6)

3L

Sol2                    

40percent (0.4)

1L

Sol3                    

1L

4L

Sol4                    

XL

3L

Sol5                    

3.5L

7L

1 + x = 3.5

x= 2.5

Required percent y = 2 . 5 3 * 1 0 0  = 83.33 percent

New answer posted

a year ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

x, a, b, y are in GP

a = xr

b = xr2

y = xr3

r = ( y x ) 1 / 3

rewrite,

a = x2/3.y1/3

b = x1/3.y2/3

a * b = x * y

a3 + b3 = x2y + y2 x

= xy (x+y)

= xy (2A) …………… [ x + y 2 = A ]

Hence, n = 2

New answer posted

a year ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

Let the side of = a

CD = a/2

Let EC = x

In GEC

GE/EC = tan60 = 3

GE = x 3

DE = a/2 – x = FG = HF

GE = HG

x3=a2−x+a2−x

x 3 = a – 2x

x = a3+2

GE = x 3 = a33+2

r = side of square ÷ 2

r= a34+23

ratio = a/r

= a (4+23)a3

= 4+23)3=43+2

New answer posted

a year ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

The potential V at any point, at distance r from centre of dipole = KPcosθ r 2

At axial point where  θ=0? , V=KPr2=9*109*4*10−622=9*103 V

At axial point where  θ=180? , V=−KPr2=−9*103 V

New answer posted

a year ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

(d):3515.2 – 3380 = 135.2 = SI on Rs. 3380 for one year.

By SI formula, 135.2 = 3 3 8 0 * R * 1 1 0 0  or R = 4 %

Now we have 3380 = P (1.04)2 or P = Rs. 3125

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