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Class 12th Physics

The material filled between the plates of a parallel plate capacitor has resistivity 200 The value of capacitance of the capacitor is 2 pF. If a potential difference of 40V is applied across the plates of the capacitor, then the value of leakage current flowing out of the capacitor is: (given the value of relative permittivity of material is 50)

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Vishal Baghel

Contributor-Level 10

for discharging RC – circuit

$q = q_{0} e^{\frac{- t}{τ}}$

$l = \frac{d q}{d t} = \frac{q_{0}}{τ} e^{- t / τ}$

$τ = C R = (\frac{k ε_{0} A}{d}) (ρ \frac{d}{A}) [? l = d]$

$l_{m a x} = \frac{q_{0}}{ρ k ε_{0}} = \frac{2 * 1 0^{- 12} * 40}{200 * 50 * 8.85 * 1 0^{- 12}}$

= 0.9 mA

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5 months ago

Class 12th English

Directions for questions: Answer the following questions based on the information given below.

The table below presents the revenue (in million rupees) of four firms in three states. These firms, F1, F2., F3. And F4. are disguised in the table as A, B, C and D, in no particular order.

States	Firm A	Firm B	Firm C	Firm D
S1	49	82	80	55
S2	69	72	70	65
S3	72	63	72	65

Further, it is known that:

In the state of S3, F3. has the highest market share.

F2.'s aggregate revenue differs from F2.'s by Rs. 5 Crore.

What can be said regarding the following two statements?

Statement I: F4. has the lowest share in S3 market.

Statement II: F1's total revenue is more than Profitable Ltd.

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Payal Gupta

Contributor-Level 10

As F3. has the highest market share hence Truthful Ltd. can be A or C. From neutral statement either B and C are aggressive and honest or A and D are aggressive and honest. According to statement (I), B is profitable, then A and D are aggressive and honest. Then honest total revenue cannot be more than that of profitable, hence statement (II) is false.

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5 months ago

Class 12th English

Two traders, T1 and T2, were involved in the buying and selling of MCS shares over five trading days. At the beginning of the first day, the MCS share was priced at Rs. 100, while at the end of the fifth day it was priced at Rs. 110. At the end of each day, the MCS share price either went up by Rs. 10, or else, it came down by Rs. 10. Both T1 and T2 took buying and selling decisions at the end of each trading day.

The beginning price of MCS share on a given day was the same as the ending price of the previous day.

T1 and T2 started with the same number of shares and amount of cash, and had enough of both. Below are some addition

...more

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Payal Gupta

Contributor-Level 10

	Day 1	Day 2	Day 3	Day 4	Day 5
Start Price	100	90	80	90	100
End Price	90	80	90	100	110

Assume initial number of share with T1 and T2 is X. In the above table T1 by 10 share each on day 1, day 2 and sold 10 shares and day 3, day 4 and day 5.

Total share with T1 is X – 10.

In the above T2 buy share only on day 2.

Total shares with T2 is X + 10.

T2 had 20 shares more than T1.

Therefore at the end of day 3 the price of share is Rs. 90

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5 months ago

Class 12th Atoms

An particular hydrogen like ion emits radiation of frequency 2.92 * 10¹⁵ Hz when it makes transition from n = 3 to n = 1. The frequency in Hz of radiation emitted in transition from n = 2 to n = 1 will be:

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Vishal Baghel

Contributor-Level 10

$h f_{1} = R (\frac{1}{1^{2}} - \frac{1}{3^{2}}) = R * \frac{8}{9}$

$h f_{2} = R (\frac{1}{1^{2}} - \frac{1}{2^{2}}) = R * \frac{3}{4}$

$\frac{f_{1}}{f_{2}} = \frac{8 / 9}{3 / 4} = \frac{32}{27}$

f₂ = f₁x $(\frac{27}{32})$

$= (2.92 * 1 0^{15}) * (\frac{27}{32})$

$= 2.46 * 1 0^{15} H z$

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5 months ago

Class 12th English

The beginning price of MCS share on a given day was the same as the ending price of the previous day.

T1 and T2 started with the same number of shares and amount of cash, and had enough of both. Below are some addition

...more

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Payal Gupta

Contributor-Level 10

	Day 1	Day 2	Day 3	Day 4	Day 5
Start Price	100	110	120	130	120
End Price	110	120	130	120	110

Let initial amount with T1 and Michal is .

T1 sold shares on Day 1, Day 2, Day 3, whereas buys shares on Day 4 and Day 5.

Total money with T1 is = Y + 110 * 10 + 120 * 10 + 130 * 10 – 120 * 10 – 110 * 10 = Y + 1300

Total money with T2 = Y + 1200

Total money with T2 = Y + 120 * 10 + 130 * 10 + 120 * 10 = Y + 3700

Total money with T2 & T1 = 2Y + 5000.

Therefore maximum possible increase is 5000.

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5 months ago

Class 12th Dual Nature of Radiation and Matter

The de-Broglie wavelength of a particle having kinetic energy E is $λ .$ How much extra energy must be given to this particle so that the de-Broglie wavelength reduces to 75% of the initial value?

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alok kumar singh

Contributor-Level 10

$λ' = λ * \frac{75}{100} = \frac{3}{4} λ$

$λ = \frac{h}{p} = \frac{h}{\sqrt[]{2 m E}}$

$\Rightarrow \frac{E'}{E} = {(\frac{λ}{λ'})}^{2} = {(\frac{4}{3})}^{2}$

$\Rightarrow E' = \frac{16}{9} E$

Extra energy required,

$Δ E = E' - E = \frac{7}{9} E$

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5 months ago

Class 12th English

Directions questions: Answer the following questions based on the information given below.

The beginning price of MCS share on a given day was the same as the ending price of the previous day.

T1 and T2 started with th

...more

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Payal Gupta

Contributor-Level 10

	Day 1	Day 2	Day 3	Day 4	Day 5
Start Price	100	90	100	110	120
End Price	90	80	110	120	110

Let initial amount with T1 and T2 is Y.

Total money with T1 = Y – 900 + 1000 + 1100 + 1200 – 1100 = Y + 1300

Total money with T2 = Y + 1200

Therefore difference between T1 and T2 is Rs. 100 and Number of shares with T2 and T1 is same.

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5 months ago

Class 12th Physics

If you are provided a set of resistance 2 $Ω$ , 4 $Ω$ , 6 $Ω$ and 8 $Ω$ . Connected these resistances so as to obtain an equivalent resistance of $\frac{46}{3} Ω .$

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alok kumar singh

Contributor-Level 10

$R_{e q} = \frac{2 * 4}{2 + 4} + 6 + 8 = \frac{46}{3} Ω$

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