Class 12th

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New answer posted

8 months ago

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A
alok kumar singh

Contributor-Level 10

Total 3 streo- isomers

New answer posted

8 months ago

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V
Vishal Baghel

Contributor-Level 10

Data contradiction.

New answer posted

8 months ago

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V
Vishal Baghel

Contributor-Level 10

Common tangents

T 1 : y = m x ± 4 m 2 + 9      

T 2 : y = m x ± 4 2 m 2 1 3    

So, 4m2 + 9 = 42 m2 – 13 Þ m =   ± 2

  c = ± 5              

So tangent  y = ± 2 x ± 5

y = 2x + 5 does not pass through 4th quadrant compare this tangent with T = 0 to get pt. of intersection

x x 2 4 2 y y 2 1 4 3 = 1 x 2 = 8 4 5

New answer posted

8 months ago

0 Follower 22 Views

A
alok kumar singh

Contributor-Level 10

Mole of polyhydric alcohol =  1 . 8 4 * 1 0 3 9 2 = 2 . 0 * 1 0 5 m o l e .

Mole of H2 gas produced = 1 . 3 4 4 2 2 4 0 0 = 6 . 0 * 1 0 5 m o l e .  

No of -OH gp present =  6 . 0 * 1 0 5 2 . 0 * 1 0 5 = 3

New answer posted

8 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

f ( x ) = 2 3 0 3 f ( λ 2 x 3 ) d λ

Substitute λ 2 x 3 = t

f ( x ) = 1 x 0 x f ( t ) t d t

differentiate using leibneitz rule

x . f ' ( x ) + f ( x ) . 1 2 x = f ( x ) x

f (1) = 3 f ( x ) = 3 x

 

New answer posted

8 months ago

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A
alok kumar singh

Contributor-Level 10

Only H2S2O8 has per-oxo bond.

 

New answer posted

8 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Oxidation state of Co = 3

And co-ordination No = 6

Sum = 3 + 6 = 9

New answer posted

8 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

Find a, α

( α 2 + α 2 3 ) + ( α 2 α 2 1 ) 5 = 0                

α = 2      

zx differentiate the curve

2 x + 2 y . y 1 + 5 ( x 2 y 2 1 ) 4 ( 2 x 2 y ) = 0 ……. (i)

differentiate equation (i)

( α , α ) y ' ' = 2 3 4 2          

New answer posted

8 months ago

0 Follower 9 Views

A
alok kumar singh

Contributor-Level 10

λ t = l n N o N t

0 . 6 9 3 t 1 / 2 * t = l n 1 N t

 Or  0.693*10030=ln1Nt

  1 N t = 1 0

N t = 1 1 0 = 0 . 1              

Or Nt = 1 * 10-1   μ g

New answer posted

8 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

V = 1 3 π r 2 h

V = π 8 h 3 t a n 2 α

d v d t = π h 2 t a n 2 α . d h d t

CSA = π r l

d ( C S A ) d t = 1 5 1 6 π 2 h . d h d t

1 5 8 * 2 3 = 5 m 2 / h r s

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