Class 12th
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New answer posted
8 months agoContributor-Level 10
No. of moles =
Moles of benzaldehyde =
Mass of benzaldehyde = 5 * 10-2 *106 = 5.3 gm
= 530 * 10-2 gm
New answer posted
8 months agoNew answer posted
8 months agoContributor-Level 10
Bauxite = AlOx (OH)3-2x (where O < x < 1)
Siderite = FeCO3
Cuprite = Cu2O
Calamine = ZnCO3
Haemetite = Fe2O3
Kaolinite = Al2 (OH)4Si2O5
Malachite = CuCO3 Cu (OH)2
Magneite = Fe3O4
Sphalerite = ZnS
Limonite = Fe2O3.3H2O
New answer posted
8 months agoContributor-Level 10
C = 500
In this LC – oscillation
q = q0 cos
=
So, imax =
= 10A

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