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Class 12th Physics

The metallic bob of simple pendulum has the relative density. 5 The time period of this pendulum is 10 s. If the metallic bob is immersed in water, then the new time period becomes $5 \sqrt[]{x} s .$ The value of x will be_______.

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Payal Gupta

Contributor-Level 10

g_eff = g – $(\frac{ρ_{w}}{ρ_{b}}) g$

$T = 2 π \sqrt[]{\frac{l}{g}}$

$T' = 2 π \sqrt[]{\frac{l}{g_{e f f}}}$

$\Rightarrow T' = \sqrt[]{\frac{5}{4}} T$

= $\sqrt[]{\frac{5}{4}} * 10$

= $5 \sqrt[]{5} s e c$

So, x = 5

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Class 12th Guru Gobind Singh Indraprastha University

Can I do BCA at IPU University if I don't have computer science or math in class 12th?

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Khushi Jaiswal

Contributor-Level 10

Yes you can pursue a BCA at IPU University even if you did not have computer Science or math in class 12 provided you have studied one of the specified subject related to computer Science or alternatively have completed a 3 year Diploma in Engineering with a minimum of 50% aggregate

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Class 12th Physics Wave Optics

Nearly 10% of the power of a 110 W light bulb is converted to visible radiation. The change in average intensities of visible radiation, at a distance of 1 m from the bulb to a distance of 5 m is a * 10^?2 W/m². The value of 'a' will be________.

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Payal Gupta

Contributor-Level 10

P = 10% of 110W = 11W

(Visible)

$I_{1} - I_{2} = \frac{ρ}{4 π} (\frac{1}{r_{1}^{2}} - \frac{1}{r_{2}^{2}})$

$= \frac{11}{4 * \frac{22}{7}} (\frac{1}{1} - \frac{1}{25})$

$\frac{7}{8} * (\frac{24}{25}) = a * 1 0^{- 2} W / m^{2}$

$\frac{28 * 24}{8} * 1 0^{- 2} = a * 1 0^{- 2}$

⇒ 84 * 10^-2 = a * 10^-2 ⇒ a = 84

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Class 12th Mahatma Jyoti Rao Phoole University

Can I get admission in Mahatma Jyoti Rao Phoole University for BPharma courses with 60% in Class 12th?

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Saurabh Khanduri

Contributor-Level 10

Yes, candidateswho have secured 60% or higher aggregate in Class 12 board exams are eligible for admissions into the BPharma courses of Mahatma Jyoti Rao Phoole University. The admission is done on merit basis, taking into account the total aggregate of scored by a candidate in their Class 12 board exams. The Mahatma Jyoti Rao Phoole University accepts candidates who have scored a minimum of 50% aggregate in their Class 12 board exams.

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Class 12th Chemistry

If O₂ gas is bubbled through water at 303 K, the number of millimoles of O₂ gas that dissolve in 1 litre of water is______________. (Nearest integer)

(Given: Henry’s Law constant for O₂ at 303 K is 46.82 k bar and partial pressure of O₂ = 0.920 bar)

(Assume solubility of O₂ in water in too small, nearly negligible)

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Class 12th Chemistry

Ionic radii of cation A⁺ and anion B^- are 102 and 181 pm respectively. These ions are allowed to crystallize into an ionic solid. This crystal has cubic close packing for B^-. A⁺ is present in all octahedral voids. The edge length of the unit cell of the crystal AB is________ pm.

(Nearest integer)

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Payal Gupta

Contributor-Level 10

$d = \frac{Z M}{N_{A} a^{3}} = \frac{4 * 58.5}{6.02 * 1 0^{23} * a^{3}}$

$43.1 = \frac{4 * 58.5}{6.02 * 1 0^{23} * a^{3}}$

$∴ a = 2.08 * 1 0^{- 8} c m$

$∴ r_{N a^{+}} + r_{C l^{-}} = 1.04 * 1 0^{- 10}$ m

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Class 12th Chemistry Electrochemistry

Resistance of a conductivity cell (cell constant 129 m^-¹) filled with 74.5 ppm solution of KCl is $100 Ω$ (labeled as solution 1). When the same cell is filled with KCl solution of 149 ppm, the resistance is $50 Ω$ (labeled as solution 2). The ratio of molar conductivity of solution 1 and solution 2 is i.e. $\frac{\land_{1}}{\land_{2}} = x * 1 0^{- 3} .$ The value of x is________. (Nearest integer)

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Payal Gupta

Contributor-Level 10

Molar mass of C₇H₅N₃O₆= 12 * 7 + 1 * 5 + 14 * 3 + 16 * 6 = 84 + 42 + 96 = 227 g/mol

Number of moles = $\frac{681}{227}$ = 3 mol

$∴$ number of N-atoms

$= 3 * 6.02 * 1 0^{23} * 3 = 9 * 6.02 * 1 0^{23}$

$= 5418 * 1 0^{21}$

$∴ x = 5418$

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a year ago

Class 12th Physics

If the potential barrier across a p-n junction is 0.6 V. Then the electric field intensity, in the depletion region having the width of 6 * 10^-⁶m, will be________ * 10⁵ N/C.

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Vishal Baghel

Contributor-Level 10

As, Ed = VB

$∴ E = \frac{V_{B}}{d} = \frac{0.6}{6 * 1 0^{- 6}} = 1 * 1 0^{5} N / C$

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a year ago

Class 12th Physics

The X-Y plane be taken as the boundary between two transparent media M₁ and M₂. M₁ in $z \geq 0$ has a refractive index of $\sqrt[]{2}$ and M₂ with Z < 0 has refractive index of $\sqrt[]{3} .$ A ray of light travelling in M₁ along the direction given by the vector $\vec{P} = 4 \sqrt[]{3} \hat{i} - 3 \sqrt[]{3} \hat{j} - 5 \hat{k},$ is incident on the plane of separation. The value of difference between the angle of incident in M₁ and the angle of refraction in M₂ will be_______ degree.

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Vishal Baghel

Contributor-Level 10

For angle of incidence 'i' :-

cos I = $\frac{5}{\sqrt[]{48 + 27 + 25}} = \frac{5}{\sqrt[]{100}}$

=> I = 60°

Using snell's law :-

$μ_{1} s i n i = μ_{2} s i n r$

sin r = $\frac{\sqrt[]{2}}{\sqrt[]{3}} s i n 60 ° = \sqrt[]{\frac{2}{3}} * \frac{\sqrt[]{3}}{2} = \frac{1}{\sqrt[]{2}}$

$∴ r = 45 °$

So, difference, I – r = 60° - 45² = 15°

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Class 12th Physics Moving Charges and Magnetism

A wire of length 314cm carrying current of 14A is bent to form a circle. The magnetic moment of the coil is_________ A -m². [Given π = 3.14]

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Vishal Baghel

Contributor-Level 10

^{$l = 2 π r$}

^{$\Rightarrow 314 c m = 2 * 3.14 r$}

^{$\Rightarrow r = \frac{1}{2} m = 0.5 m$}

^{$μ = i A$}

^{$= 14 * π r^{2}$}

^{$= 1 4^{2} * \frac{22}{7} * \frac{1}{4} = 11$}

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