Class 12th

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New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

l i m n → ∞ ( n + 1 n ) k − 1 1 n ∑ r = 1 n ( k + r n )

= 3 3 ∫ 0 1 x k d x

New answer posted

a year ago

0 Follower 17 Views

V
Vishal Baghel

Contributor-Level 10

f ( x ) = { | 4 x 2 − 8 x + 5 | ,     i f     8 x 2 − 6 x + 1 ≥ 0 [ 4 x 2 − 8 x + 5 ] ,     i f     8 x 2 − 6 x + 1 < 0

x = 1 4 , 2 − 2 2 , 1 2

New answer posted

a year ago

0 Follower 29 Views

V
Vishal Baghel

Contributor-Level 10

General term

= 1 5 C r ( t 2 x 1 5 ) 1 5 − r ( ( 1 − x ) 1 1 0 t ) r    

for term independent on t

2 (15 – r) – r = 0

⇒ r = 1 0          

∴ T 1 1 = 1 5 C 1 0 * ( 1 − x )

Maximum value of x (1 – x) occur at

x =  1 2

New answer posted

a year ago

0 Follower 14 Views

V
Vishal Baghel

Contributor-Level 10

Here,

A = [ 2 − 1 − 1 1 0 − 1 1 − 1 0 ]            

we get A2 = A and similarly, for

B = A − I = [ 1 − 1 − 1 1 − 1 − 1 1 − 1 − 1 ]            

We get B2 = -B ⇒  B3 = B

∴ A n + ( ω B ) n = A + ( ω B ) n       f o r       n ∈ N

For ω n  to be unity n shall be multiple of 3 and for Bn to be B. n shell be 3, 5, 7, ….9

∴ n = { 3 , 9 , 1 5 , . . . . . 9 9 }     

Number of elements = 17.

New answer posted

a year ago

0 Follower 97 Views

V
Vishal Baghel

Contributor-Level 10

2 (only 2 carbon will chiral in product form)

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

  C o 3 +  will not get oxidized, so will not liberate H2 gas upon reaction with acidic solution.

No. of unpaired electron = 4

Spin only magnetic moment = 4 ( 4 + 2 ) B M = 2 4 B M ≈ 5 B M

New answer posted

a year ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

Complex absorbing minimum wavelength of light means the value of Δ  for it is maximum.

That complex will be [ C o ( C N ) 6 ] 3 −

C o 3 + ⇒ 3 d 6 4 s 0 ⇒ t 2 g 6 e g 0

No. of unpaired electron = 0

New answer posted

a year ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

( t 1 / 2 ) l ( t 1 / 2 ) I I = ( P I P I I ) 1 − n ⇒ n = 1

New answer posted

a year ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

  A n o d e : ( Z n → Z n 2 + + 2 e ) * x

C a t h o d e : ( S n x + + x e → S n ) * 2 _      

Net call reaction :  x Z n + 2 S n x + → x Z n 2 + + 2 S n ( n = 2 x )

Using Nernst equation

No. of electron involved = 4

New answer posted

a year ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

d = 2 R h          

d = 2 * 6 4 0 0 * h * 1 0 − 3 ( h     i n     m )

Area =  π d 2

= ( π * 2 * 6 4 0 0 * h * 1 0 − 3 ) km2

h = 150m

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