Class 12th

Given below are two statements:

Statement I : The electric force changes the speed of the charged particle and hence charges its kinetic energy; whereas the magnetic force does not change like kinetic energy of the charged particle.

Statement II : The electric force accelerates the positively charged particle perpendicular to the direction of electric field. The magnetic force accelerated the moving charged particle along the direction of magnetic field.

In the light of the above statements, chose the most appropriate answer from the option given below

Two long current carrying conductors are placed parallel to each other at a distance of 8 cm between them. The magnitude of magnetic field produced at mid-point between the two conductors due to current flowing in them is 300 $\mu T$ . the equal current flowing in the two conductors is

A capacitor is discharging through a resistor R. Consider in time t₁ the energy stored in the capacitor reduces to half of its initial value and in time t₂, the charge stored in the capacitor reduces to half of its initial value and in time t₂ the charge stored reduces to one eight of its initial value. The ratio t₁/t₂ will be

The electric field at a point associated with a light wave is given by

E = 200 $\left[sin\left(6*10^{15}\right)t+sin\left(9*10^{15}\right)t\right]V{m}^{-1}$

Given : h = 4.14 * 10^-15 eVs

If the light fall on a metal surface having a work function of 2.50 eV, the maximum kinetic energy of the photoelectrons will be

Let A = $\left\{Z\in C:\left|\frac{z+1}{z-1}\right|<1\right\}$and B = $\left\{z\in C:arg\left(\frac{z-1}{z+1}\right)=\frac{2\pi }{3}\right\}.$Then $A\cup B$ is

Let $\Delta ,\nabla \in \left\{\wedge ,\vee \right\}$ be such that $p\nabla q\Rightarrow \left(\left(p\Delta q\right)\nabla r\right)$ is a tautology. Then $\left(p\nabla q\right)\Delta r$ is logically equivalent to