Class 12th

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New answer posted

11 months ago

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V
Vishal Baghel

Contributor-Level 10

It is aldol condensation.

New answer posted

11 months ago

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V
Vishal Baghel

Contributor-Level 10

Number of sp2 carbon = 8

New answer posted

11 months ago

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P
Payal Gupta

Contributor-Level 10

P (H) = x . P (T) = 1 – x

P (4H. 1T) = P (5H)

               

6x = 5 = 0     x = 5 6        

P (atmost 2H)

P ( O H , 5 T ) + P ( 1 H , 4 T ) + P ( 2 H , 3 T )

= 1 6 5 ( 1 + 2 5 + 2 5 0 ) = 2 7 6 6 5 = 4 6 6 4                   

New answer posted

11 months ago

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V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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11 months ago

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V
Vishal Baghel

Contributor-Level 10

CoCl3.NH3 + AgNO3   A g C l ( 2 m o l )

[ C o ( N H 3 ) 5 C l ] C l 2 + A g N O 3 A g C l ( 2 m o l )            

x = 5

New answer posted

11 months ago

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V
Vishal Baghel

Contributor-Level 10

M n 2 + t 2 g 1 1 1 e g 1 1

(Number of unpaired electron = 5)

μ S = 3 5 = 5 . 9 1 6

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11 months ago

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V
Vishal Baghel

Contributor-Level 10

  K = A . e E a / R T = ( 6 . 5 * 1 0 2 ) e 2 6 0 0 0 K / T

E a 8 . 3 1 4 = 2 6 0 0 0

 Ea = 216.164kJ/mol 216

New answer posted

11 months ago

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V
Vishal Baghel

Contributor-Level 10

H2 (g) + Cu2+ (aq)   2H+ (aq) + Cu (s)

  E c e l l = E c e l l 0 2 . 3 0 3 R T n f l o g Q              

              0.31 = 0.34 -   0 . 0 6 2 l o g [ H + ] C u 2 +

[ C u 2 + ] = 1 0 7 ( ? [ H + ] = 1 0 3 )        

              x = 7

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