Class 12th

Consider aiming a beam of free electrons towards free protons. When-they scatter, an electron and a proton cannot combine to produce a H-atom.
(a) Because of energy conservation
(b) Without simultaneously releasing energy in the form of radiation
(c) Because of momentum conservation
(d) Because of angular momentum conservation

An ionised H-molecule consists of an electron and two protons. The protons are separated by a small distance of the order of angstrom. In the ground state,
(a) The electron would not move in circular orbits
(b) The energy would be (2)⁴times that of a H-atom
(c) The electrons, orbit would go around the protons
(d) The molecule will soon decay in a proton and a H-atom

A set of atoms in an excited state decays
(a) In general to any of the states with lower energy
(b) Into a lower state only when excited by an external electric field
(c) All together simultaneously into a lower state
(d) To emit photons only when they collide.

Two H atoms in the ground state collide inelastically. The maximum amount by which their combined kinetic energy is reduced is
(a) 10.20 eV  

(b) 20.40eV    

(c) 13.6 eV

0₂ molecule consists of two oxygen atoms. In the molecule, nuclear force between the nuclei of the two atoms
(a) Is not important because nuclear forces are short-ranged
(b) Is as important as electrostatic force for binding the two atoms
(c) Cancels the repulsive electrostatic force between the nuclei
(d) Is not important because oxygen nucleus have equal number of neutrons and protons

For the ground state, the electron in the H-atom has an angular .momentum = h, according to the simple Bohr model. Angular momentum is a vector and hence there will be infinitely many orbits with the vector pointing in all possible directions. In actuality, this is not true,
(a) Because Bohr model gives incorrect values of angular momentum
(b) Because only one of these Would Have a minimum energy
(c) Angular momentum must be in the direction of spin of electron
(d) Because electrons go around only in horizontal orbits

The simple Bohr model cannot be directly applied to calculate the energy levels of an atom with man electrons. This is because
(a) Of the electrons not being subject to a central force
(b) Of the electrons colliding with each other
(c) Of screening effects
(d) The force between the nucleus and an electron will no longer be given by Coulomb's law

The binding energy of a H-atom, considering an electron moving around a fixed nuclei (proton), is B= .

If one decides to work in a frame of reference where the electron is at rest,the proton would be moving around it.by similar arguments, the binding energy would be

B= (M=proton mass)

This last expression is not correct.

(a) N would not be integral

(b) Bohr-quantisation applies only two electron

(c) The frame in which the electron is at rest is not inertial

(d) The motion of the proton would not be in circular orbits, even approximately.

Taking the Bohr radius as a₀= 53 pm, the radius of Li⁺⁺ ion in its ground state, on the basis of Bohr's model, will be about
(a) 53 pm    

(b) 27 pm  

(c) 18 pm  

(d) 13 pm

What is the minimum energy that must be given to a H-atom in ground state so that it can emit an H_?Line in Balmer series? If the angular momentum of the system is conserved, what would be the angular momentum of such H_? photon?