Class 12th
Get insights from 11.9k questions on Class 12th, answered by students, alumni, and experts. You may also ask and answer any question you like about Class 12th
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New question posted
a year agoNew question posted
a year agoNew answer posted
a year agoContributor-Level 10
Given, A2= A.
(E) we need to calculate,
(I + A)3- 7A = I3 + A3 + 3IA (I + A) - 7A { (x + y)3 = x3 + y3 + 3xy (a + y)}

New question posted
a year agoNew answer posted
a year agoContributor-Level 10
Given, A is both symmetric and skew-symmetric.
(E) Then, A' = A ____ (1) and A' = -A ____ (2)
So using (2), A' = -A.
A = -A {eqn (I)}
A + A = 0
2A = 0
A = 0.
A is a zero matrix
So, option B is correct.
New answer posted
a year agoContributor-Level 10
We have, AB = BA. (given)
(E) P (n):AB' = B'A.
P (i):AB1 = B1A. Þ AB = BA
so, the result is true for n = 1.
Let the result be true for n = k.
P (k):ABk = BkA
Then,
P (k + 1) : ABk + 1 = A. Bk. B = BkA.B = Bk.BA
= Bk + 1.A .
So, ABk + 1 = Bk + 1A.
The result also holds for n = k + 1.
Hence, AB^n = B^n A^n holds for all natural number 'n'.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 66k Colleges
- 1.2k Exams
- 705k Reviews
- 1850k Answers






