Computer Science and Engineering

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New answer posted

11 months ago

0 Follower 15 Views

K
Kunal Lalwani

Contributor-Level 9

Students enroll in B.Tech at SASTRA University through Stream 1 using JEE Mains scores with Class 12 marks while Stream 2 relies only on Class 12 marks for admission. Your admission odds will be determined by cutoff developments together with applicant numbers and accessible seats after obtaining 80 percentile in JEE Mains . Students who obtained higher percentiles in the previous JEE Mains examination usually had a favorable standing when applying for CSE-related branches. Students should check the Class 12 merit list and corresponding cutoff scores to qualify for admission under Stream 2. Sitting for both admission streams should be

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New answer posted

11 months ago

0 Follower 7 Views

H
Himanshi Pandey

Contributor-Level 10

Candidates pursuing a BE at MSRIT can opt for the Computer Science and Engineering stream. The four-year programme is divided into eight semesters. In each semester, students have to study various subjects, each carrying certain credits. Listed below are some subjects included in the MSRIT BE in CSE curriculum:

  • Data Structures
  • Object Oriented Programming
  • Discrete Mathematical Structures
  • Microcontrollers & IoT
  • Design & Analysis of Algorithms
  • Finite Automata & Formal Languages
  • Data Communication & Networking
  • Database Systems
  • Operating Systems
  • Software Engineering & Modelling

 

New answer posted

11 months ago

0 Follower 10 Views

K
Kunal Lalwani

Contributor-Level 9

Students need to meet yearly established JEE Main scores set by Indira Gandhi University to qualify for B.Tech in Computer Science and Engineering admission. The OBC cutoff extent falls within 75-85 percentile yet the General category cutoff spans from 85-95 percentile. The counseling process occurs through the Haryana State Technical Education Society (HSTES). Prospective students need to enroll through the online system followed by selection input followed by participation in different counseling sessions. The allotted seats depend on candidate rank together with category and available seats in the program. Finalization of admission

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New answer posted

11 months ago

0 Follower 18 Views

H
Himanshi Pandey

Contributor-Level 10

COMEDK UGET is one of the accepted entrance exams for BE admission at MSRIT. Based on the last-round COMEDK UGET cut-off, BE in Computer Science & Engineering (CSE) has been the most competitive stream to secure admission to over the past three years. The institute also offers a BE in CSE (AI & ML) and BE in CSE (Data Securtiy). The MSRIT COMEDK UGET cut-off trend based on the last-round cut-off for the General category candidates is presented below:

Course202220232024
BE in Computer Science and Engineering331713581585
BE in Computer Science and Engineering (Cyber Security)502221592990
BE in Computer Science and Engineering (Artificial Intelligence & Machine Learning)435618302175

New answer posted

11 months ago

0 Follower 59 Views

S
Soumya Chaturvedi

Contributor-Level 9

For B.Tech Computer Science at Jaipur Engineering College & Research Centre (JECRC), the expected JEE Main EWS cutoff percentile ranges between 85 to 89.9 for merit scholarships, and above 90 for higher merit scholarships. 

JEE Main Percentile for Merit Scholarships:

  • 85 to 89.9: Merit Scholarship 
  • Above 90: Merit Scholarship 

New answer posted

11 months ago

0 Follower 22 Views

A
Anurag Shivam

Contributor-Level 9

For the B.Tech in Computer Science and Engineering (CSE) at SGSITS Indore, the general-EWS category closing rank in 2024 was around 39030. 

Here's a more detailed breakdown:

General-All India (Outside Home State): The closing rank for General category outside Madhya Pradesh was around 21192. 

General-Home State: The closing rank for General category within Madhya Pradesh was around 19229. 

General-EWS: The closing rank for General-EWS category was around 39030. 

2023 Closing Rank: In 2023, the closing rank for CSE was around 29903. 

2022 Closing Rank: In 2022, the closing rank for CSE was around 21192. 

New answer posted

11 months ago

0 Follower 40 Views

C
Charitha Nekkallapu

Contributor-Level 10

Yes, there is a good chance of getting admission in Jaypee Institute of Information Technology  (JIIT) for B.Tech CSE with 90% in UP Board and 70% in JEE Mains.

CSE is a competitive branch, and JIIT Noida considers JEE mains scores for admission, but there is a difference in cutoffs every year.

 

New answer posted

11 months ago

0 Follower 7 Views

I
Indrani Kumar

Contributor-Level 10

Currently, TIET has not released the cutoff for the BE course 2025 on the basis of JEE Main ranks/scores. However, to get an idea about the competitiveness of the cutoff in the previous years, candidates can check the below table: 

JEE Main Last Round Closing Rank (General-All India)

Course202220232024
BE in Computer Science and Engineering52183381454620

New answer posted

11 months ago

0 Follower 73 Views

C
Charushila Alone

Beginner-Level 5

As 97.8 is good ranking for CSE branch colleges like IITs ( Kottayam, Siri city, una), NITs, (Kottayam, nagaland, uttarakhand) can get also notable University brirla institute of technology, institute of infrastructure technology, research and management, ahmadabad also better option as their privious close rank was also around it 

New answer posted

11 months ago

0 Follower 16 Views

K
Kunal Lalwani

Contributor-Level 9

Prospective students of the B.Tech Computer Science and Engineering program at Kalyani Government Engineering College (KGEC) need to seek admission through their WBJEE ranks rather than JEE Main. The admission chances through WBJEE at position 3599 as an OBC candidate depend on previous year cut-off pattern data. OBC candidates at KGEC normally need to match the cutoff between 1500 and 2500 for CSE admission. The likelihood of securing CSE admission at Kalyani Government Engineering College is minimal but you could secure a less popular branch. Verify the most current cutoff information to remain certain.

 

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