Data Interpretation

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New answer posted

2 months ago

Two traders, T1 and T2, were involved in the buying and selling of MCS shares over five trading days. At the beginning of the first day, the MCS share was priced at Rs. 100, while at the end of the fifth day it was priced at Rs. 110. At the end of each day, the MCS share price either went up by Rs. 10, or else, it came down by Rs. 10. Both T1 and T2 took buying and selling decisions at the end of each trading day.

 

The beginning price of MCS share on a given day was the same as the ending price of the previous day.

T1 and T2 started with the same number of shares and amount of cash, and had enough of both. Below are some addition

...more
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P
Payal Gupta

Contributor-Level 10

 

Day 1

Day 2

Day  3

Day 4

Day 5

Start Price

100

90

80

90

100

End  Price

90

80

90

100

110

 

Assume initial number of share with T1 and T2 is X. In the above table T1 by 10 share each on day 1, day 2 and sold 10 shares and day 3, day 4 and day 5.

Total share with T1 is X – 10.

In the above T2 buy share only on day 2.

Total shares with T2 is X + 10.

T2 had 20 shares more than T1.

Therefore at the end of day 3 the price of share is Rs. 90

New answer posted

2 months ago

Two traders, T1 and T2, were involved in the buying and selling of MCS shares over five trading days. At the beginning of the first day, the MCS share was priced at Rs. 100, while at the end of the fifth day it was priced at Rs. 110. At the end of each day, the MCS share price either went up by Rs. 10, or else, it came down by Rs. 10. Both T1 and T2 took buying and selling decisions at the end of each trading day.

 

The beginning price of MCS share on a given day was the same as the ending price of the previous day.

T1 and T2 started with the same number of shares and amount of cash, and had enough of both. Below are some addition

...more
0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

 

Day 1

Day 2

Day  3

Day 4

Day 5

Start Price

100

110

120

130

120

End  Price

110

120

130

120

110

 

Let initial amount with T1 and Michal is .

T1 sold shares on Day 1, Day 2, Day 3, whereas buys shares on Day 4 and Day 5.

Total money with T1 is = Y + 110 * 10 + 120 * 10 + 130 * 10 – 120 * 10 – 110 * 10 = Y + 1300

Total money with T2 = Y + 1200

Total money with T2 = Y + 120 * 10 + 130 * 10 + 120 * 10 = Y + 3700

Total money with T2 & T1 = 2Y + 5000.

Therefore maximum possible increase is 5000.

New answer posted

2 months ago

Two traders, T1 and T2, were involved in the buying and selling of MCS shares over five trading days. At the beginning of the first day, the MCS share was priced at Rs. 100, while at the end of the fifth day it was priced at Rs. 110. At the end of each day, the MCS share price either went up by Rs. 10, or else, it came down by Rs. 10. Both T1 and T2 took buying and selling decisions at the end of each trading day.

 

The beginning price of MCS share on a given day was the same as the ending price of the previous day.

T1 and T2 started with the same number of shares and amount of cash, and had enough of both. Below are some addition

...more
0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

 

Day 1

Day 2

Day  3

Day 4

Day 5

Start Price

100

90

100

110

100

End  Price

90

100

110

100

100

 

Let initial amount with T1 and T2 is Y.

Total Money with T1 = Y – 900 + 1000 + 1100 + 1200 – 1100 = Y + 1300 

Total money with T2 = Y

Therefore, T1 ended up with Rs. 1300 more cash than T2.

Therefore at the end of day 4 the price of share is Rs.100.

New answer posted

2 months ago

Directions questions: Answer the following questions based on the information given below.

Two traders, T1 and T2, were involved in the buying and selling of MCS shares over five trading days. At the beginning of the first day, the MCS share was priced at Rs. 100, while at the end of the fifth day it was priced at Rs. 110. At the end of each day, the MCS share price either went up by Rs. 10, or else, it came down by Rs. 10. Both T1 and T2 took buying and selling decisions at the end of each trading day.

 

The beginning price of MCS share on a given day was the same as the ending price of the previous day.

T1 and T2 started with th

...more
0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

 

Day 1

Day 2

Day  3

Day 4

Day 5

Start Price

100

90

100

110

120

End  Price

90

80

110

120

110

 

Let initial amount with T1 and T2 is Y.

Total money with T1 = Y – 900 + 1000 + 1100 + 1200 – 1100 = Y + 1300

Total money with T2 = Y + 1200

Therefore difference between T1 and T2 is Rs. 100 and Number of shares with T2 and T1 is same.

New answer posted

2 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

Please find the answers below

New answer posted

2 months ago

Directions for question :  Answer the questions on the basis of the information given below.

Honda Motors manufactures cars in their Chennai plant. The performance of the plant for 10 consecutive years is given below. The plant when started the operations in year 2001 has a cash surplus of 10 million rupees and no stock was there in the plant. It is also known that for every unit of car manufacture 2 units of body and 3 units of engine are used.

 

P  Production (units)

S  Sales (units)

SP Selling Price (Rs./unit)

FC Fixed Cost (Million Rs.)

CB Cost of Body (per unit of body)

CE Cost of Engine (per unit of engine)

&n

...more
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P
Payal Gupta

Contributor-Level 10

Please find the answer below

New answer posted

2 months ago

In an ancient game of trading “Pirate Bay”, 6 players took part. The game is played in a manner that the players select a port each and then they trade with each other. Everything that they sent out to other player is known as exports and anything that they receive from other players is known as imports. The table below shows details of imports and exports of between those six players. The entry corresponding to a particular row i and column j gives the total amount of exports by a player i to a player j in all the previous trade rounds. For example the entry in row 2 column 4 means P2 has exported to P4 a total of 58 times. 

...more
0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

From the table above.

New answer posted

2 months ago

In an ancient game of trading “Pirate Bay”, 6 players took part. The game is played in a manner that the players select a port each and then they trade with each other. Everything that they sent out to other player is known as exports and anything that they receive from other players is known as imports. The table below shows details of imports and exports of between those six players. The entry corresponding to a particular row i and column j gives the total amount of exports by a player i to a player j in all the previous trade rounds. For example the entry in row 2 column 4 means P2 has exported to P4 a total of 58 times. 

...more
0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

From the table above.

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