Definite Integrals

Get insights from 36 questions on Definite Integrals, answered by students, alumni, and experts. You may also ask and answer any question you like about Definite Integrals

Follow Ask Question
36

Questions

0

Discussions

3

Active Users

0

Followers

New question posted

2 months ago

0 Follower 25 Views

New answer posted

2 months ago

0 Follower 7 Views

R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image 

 

New answer posted

2 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

|z|-Re (z)≤1 ⇒ √ (x²+y²)-x≤1 ⇒ √ (x²+y²)≤1+x ⇒ y²≤1+2x=2 (x+1/2).

New answer posted

2 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

I = ∫ (π/24 to 5π/24) dx/ (1+³√tan2x). Using King's rule.
2I = ∫ (π/24 to 5π/24) dx = 4π/24=π/6. I=π/12.

New question posted

2 months ago

0 Follower 3 Views

New answer posted

2 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

2(cos²θ/sin²θ) - 5/sinθ + 4 = 0
(2sinθ - 1)(sinθ - 2) = 0
sinθ = 1/2 only
∴ θ = π/6, 5π/6
↓↓
θ?, θ?
∫(π/6 to 5π/6) cos²3θdθ = ∫(π/6 to 5π/6) (1+cos6θ)/2 dθ = π/3

New answer posted

2 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

log (x + √ (x²+1) is an odd function.
f (-x) = log (-x + √ (x²+1) = log (1/ (x+√ (x²+1) = -log (x+√ (x²+1) = -f (x).
Integral of an odd function over a symmetric interval is 0.

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 682k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.