DILR Prep Tips for MBA

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New answer posted

8 months ago

Answer the questions on the basis of the information given below.

In a school when a survey is conducted on liking of subjects out of three subjects physics, chemistry mathematics then outcome is as follow.

Total number of students who like physics, chemistry and mathematics is 30, 40, 50 respectively. 10 students shown interest in all three subjects, Number of students who like physics and mathematics both is equal to number of students who like chemistry and mathematics both and is equal to 3/4 times number of students who like physics and chemistry both 15 students like only chemistry.

When class teacher saw this survey report he to

...more
0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

From the given condition g = 10,

Number of students who like both Physics and Maths = 10 + f

Number of students who like both chemistry and Maths = 10 + e

From given condition 10 + f = 10 + e or e = f

Similarly from 3rd condition ¾ (10 + e) = 10 + d

Or 30 + 3e = 40 + 4d

Or

 Since 15 students like only chemistry hence b = 15

Number of students who like only chemistry is 40

Hence e + g + d + b = 40

or e + 10 + (3e – 10)/4 + 15 = 40

or (7e – 10)/4 = 15 or 7e = 70 or e = 10

Hence a = 5, c = 20, f = e = 10, d = 5

Hence the distribution is as follows

As per the observation of  class teacher actual numbers of students who like Physics in

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New answer posted

8 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

According to given condition, we conclude:

I.    Amlia – Giana = 8

II.  Drew + Raddix = 37

III. Joanna = Drew + 8

IV. Amlia = Drew + 5

V.  Amlia + Giana = 40

Using (I) and (IV),

Amlia = 24, Giana = 16

Using (IV),

Drew = 19

Using (III),

Joanna = 27

Using (II),

Raddix = 18

Raddix shot 18 baskets and Drew shot 19 baskets.

New answer posted

8 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

As per the given information we have four teams, four couples and 4 different points

I. “Sweet Couple” won 2 points

II. Mukesh's team won 4 points more than Lina's team and Lina's team has not scored the least points. Therefore, only possible options is Lina has 4 points and Mukesh has 8 points. It also means that Mukesh (with point 8) is not with Lina, and both of them  does not belongs to “Sweet Couple”

III. “Just Singing” won 6 points. Hence Mukesh and Lina do not belongs to “Just Singing”

IV. Sanjeev's team scored 4 points. While from (II) we have seen that Lina has also 4 points hence Sanjeev and Lina belongs to s

...more

New answer posted

8 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

As per the given information we have four teams, four couples and 4 different points

I. “Sweet Couple” won 2 points

II. Mukesh's team won 4 points more than Lina's team and Lina's team has not scored the least points. Therefore, only possible options is Lina has 4 points and Mukesh has 8 points. It also means that Mukesh (with point 8) is not with Lina, and both of them  does not belongs to “Sweet Couple”

III. “Just Singing” won 6 points. Hence Mukesh and Lina do not belongs to “Just Singing”

IV. Sanjeev's team scored 4 points. While from (II) we have seen that Lina has also 4 points hence Sanjeev and Lina belongs to s

...more

New answer posted

8 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

As per the given information we have four teams, four couples and 4 different points

I. “Sweet Couple” won 2 points

II. Mukesh's team won 4 points more than Lina's team and Lina's team has not scored the least points. Therefore, only possible options is Lina has 4 points and Mukesh has 8 points. It also means that Mukesh (with point 8) is not with Lina, and both of them  does not belongs to “Sweet Couple”

III. “Just Singing” won 6 points. Hence Mukesh and Lina do not belongs to “Just Singing”

IV. Sanjeev's team scored 4 points. While from (II) we have seen that Lina has also 4 points hence Sanjeev and Lina belongs to s

...more

New answer posted

8 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

As per the given information we have four teams, four couples and 4 different points

I. “Sweet Couple” won 2 points

II. Mukesh's team won 4 points more than Lina's team and Lina's team has not scored the least points. Therefore, only possible options is Lina has 4 points and Mukesh has 8 points. It also means that Mukesh (with point 8) is not with Lina, and both of them  does not belongs to “Sweet Couple”

III. “Just Singing” won 6 points. Hence Mukesh and Lina do not belongs to “Just Singing”

IV. Sanjeev's team scored 4 points. While from (II) we have seen that Lina has also 4 points hence Sanjeev and Lina belongs to s

...more

New answer posted

8 months ago

Read the information carefully and answer the questions given below.

Bus route no. 971 has exactly six stops on its route. Any bus plying on this route starts from the initial position, then stops first at stop one and then stops at two, three, four, five, and six respectively. After the bus reaches stop six, the bus turns and returns to its initial position and repeats the cycle. Buses are not allowed to carry people on its return journey.

Following are the six stops – Lokhand Wala, Saket Xing, Kanpur, Aligarh, Peetampura, and Rajghat in no particular order, Further, following observations have been made regarding the stops on this

...more
0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

Following is the structure of the stops on this route:

Case I:

Aligarh

Rajghat

Peetampura

Kanpur

Lokhand wala

Saket Xingh

Stop 1

Stop 2

Stop 3

Stop 4

Stop 5

Stop 6

Case II:

Kanpur

Lokhand wala

Peetampura

Aligarh

Rajghat

Saket Xingh

Stop 1

Stop 2

Stop 3

Stop 4

Stop 5

Stop 6

New answer posted

8 months ago

Read the information carefully and answer the questions given below.

Bus route no. 971 has exactly six stops on its route. Any bus plying on this route starts from the initial position, then stops first at stop one and then stops at two, three, four, five, and six respectively. After the bus reaches stop six, the bus turns and returns to its initial position and repeats the cycle. Buses are not allowed to carry people on its return journey.

Following are the six stops – Lokhand Wala, Saket Xing, Kanpur, Aligarh, Peetampura, and Rajghat in no particular order, Further, following observations have been made regarding the stops on this

...more
0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

Following is the structure of the stops on this route:

Case I:

Aligarh

Rajghat

Peetampura

Kanpur

Lokhand wala

Saket Xingh

Stop 1

Stop 2

Stop 3

Stop 4

Stop 5

Stop 6

Case II:

Kanpur

Lokhand wala

Peetampura

Aligarh

Rajghat

Saket Xingh

Stop 1

Stop 2

Stop 3

Stop 4

Stop 5

Stop 6

New answer posted

8 months ago

Read the information carefully and answer the questions given below.

Bus route no. 971 has exactly six stops on its route. Any bus plying on this route starts from the initial position, then stops first at stop one and then stops at two, three, four, five, and six respectively. After the bus reaches stop six, the bus turns and returns to its initial position and repeats the cycle. Buses are not allowed to carry people on its return journey.

Following are the six stops – Lokhand Wala, Saket Xing, Kanpur, Aligarh, Peetampura, and Rajghat in no particular order, Further, following observations have been made regarding the stops on this

...more
0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

Following is the structure of the stops on this route:

Case I:

Aligarh

Rajghat

Peetampura

Kanpur

Lokhand wala

Saket Xingh

Stop 1

Stop 2

Stop 3

Stop 4

Stop 5

Stop 6

Case II:

Kanpur

Lokhand wala

Peetampura

Aligarh

Rajghat

Saket Xingh

Stop 1

Stop 2

Stop 3

Stop 4

Stop 5

Stop 6

New answer posted

8 months ago

Directions for questions: Read the information carefully and answer the questions given below.

Bus route no. 971 has exactly six stops on its route. Any bus plying on this route starts from the initial position, then stops first at stop one and then stops at two, three, four, five, and six respectively. After the bus reaches stop six, the bus turns and returns to its initial position and repeats the cycle. Buses are not allowed to carry people on its return journey.

Following are the six stops – Lokhand Wala, Saket Xing, Kanpur, Aligarh, Peetampura, and Rajghat in no particular order, Further, following observations have been made re

...more
0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

Following is the structure of the stops on this route:

Case I:

Aligarh

Rajghat

Peetampura

Kanpur

Lokhand wala

Saket Xingh

Stop 1

Stop 2

Stop 3

Stop 4

Stop 5

Stop 6

Case II:

Kanpur

Lokhand wala

Peetampura

Aligarh

Rajghat

Saket Xingh

Stop 1

Stop 2

Stop 3

Stop 4

Stop 5

Stop 6

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