DILR Prep Tips for MBA
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New question posted
7 months agoNew answer posted
7 months agoContributor-Level 10
Friends | Wives | Venue of wedding | Month |
Amar | Veena | Ahmedabad | July |
Deepu | Geetika | Kolkata | February |
Manoj | Ipsita | Chennai | November |
Preet | Brinda | Mumbai | December |
Rajan | Hema | Delhi | April |
Sahil | Jasmine | Benguluru | September |
New answer posted
7 months agoContributor-Level 10
Friends | Wives | Venue of wedding | Month |
Amar | Veena | Ahmedabad | July |
Deepu | Geetika | Kolkata | February |
Manoj | Ipsita | Chennai | November |
Preet | Brinda | Mumbai | December |
Rajan | Hema | Delhi | April |
Sahil | Jasmine | Benguluru | September |
New answer posted
7 months agoContributor-Level 10
Deceleration in 8th hour = 20 km/h2
Speed at the end of 8th hour = 50 km/h
Speed will be zero after 't' h where 0 = 50 – 20 * t
= speed will be zero at 10 h 30 minutes.
New answer posted
7 months agoContributor-Level 10
Name | Blue | Green | Red | Yellow | Salary |
Paul | * | ? | * | * | 30 |
Krishna | * | * | ? | * | 110 |
Laxman | * | * | * | ? | 50 |
Som | ? | * | * | * | 80 |
New answer posted
7 months agoContributor-Level 10
Acceleration = change in velocity/h
= 20 km/h2 in 1st, 3rd and 4th h
New answer posted
7 months agoContributor-Level 10
Name | Blue | Green | Red | Yellow | Salary |
Paul | * | ? | * | * | 30 |
Krishna | * | * | ? | * | 110 |
Laxman | * | * | * | ? | 50 |
Som | ? | * | * | * | 80 |
New answer posted
7 months agoContributor-Level 10
Distance covered in 0 – 2 hours slot = 10 + 20 = 30 km
Distance covered in 2 – 4 hours slot = 80 km
Distance covered in 4 – 6 hours slot = 120 km
Distance covered in 6 – 8 hours slot = 125 km
New answer posted
7 months agoContributor-Level 10
Name | Blue | Green | Red | Yellow | Salary |
Paul | * | ? | * | * | 30 |
Krishna | * | * | ? | * | 110 |
Laxman | * | * | * | ? | 50 |
Som | ? | * | * | * | 80 |
New answer posted
7 months agoContributor-Level 10
The average speed in first hour = 10 km/hr
Average speed represented by the graph
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