DILR Prep Tips for MBA
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New answer posted
7 months agoContributor-Level 10
(b)
Required cost
= (240 * 15) + (1200 * 30) + (840 * 18)
= Rs. 54720
New answer posted
7 months agoContributor-Level 10
(c)
F3 to W4 to R3 is maximum. Therefore, option (c) is the correct answer.
New answer posted
7 months agoContributor-Level 10
(c)
F4 to W4 to R4 is the lowest. Therefore, option (c) is the correct answer.
New answer posted
7 months agoContributor-Level 10
(b)
F5 to W1 to R5 is maximum. Therefore, option (b) is the correct answer.
New answer posted
7 months agoContributor-Level 10
(b)
F3 to W2 to R6 is the lowest. Therefore, option (b) is the correct answer.
New answer posted
7 months agoContributor-Level 10
Let us make a table for the time taken:
| Patna | Mumbai | Calcutta | Chennai | Bangalore |
Patna | - | 4 | 5 | 3.75 | 10 |
Mumbai | 4 | - | 6.666667 | 10 | 12.5 |
Calcutta | 5 | 6.666667 | - | 12.5 | 12 |
Chennai | 3.75 | 10 | 12.5 | - | 4 |
Bangalore | 10 | 12.5 | 12 | 4 | - |
c
New answer posted
7 months agoContributor-Level 10
Let us make a table for the time taken:
| Patna | Mumbai | Calcutta | Chennai | Bangalore |
Patna | - | 4 | 5 | 3.75 | 10 |
Mumbai | 4 | - | 6.666667 | 10 | 12.5 |
Calcutta | 5 | 6.666667 | - | 12.5 | 12 |
Chennai | 3.75 | 10 | 12.5 | - | 4 |
Bangalore | 10 | 12.5 | 12 | 4 | - |
a
New answer posted
7 months agoContributor-Level 10
Let us make a table for the time taken:
| Patna | Mumbai | Calcutta | Chennai | Bangalore |
Patna | - | 4 | 5 | 3.75 | 10 |
Mumbai | 4 | - | 6.666667 | 10 | 12.5 |
Calcutta | 5 | 6.666667 | - | 12.5 | 12 |
Chennai | 3.75 | 10 | 12.5 | - | 4 |
Bangalore | 10 | 12.5 | 12 | 4 | - |
(c)
New answer posted
7 months agoContributor-Level 10
Let us make a table for the time taken:
| Patna | Mumbai | Calcutta | Chennai | Bangalore |
Patna | - | 4 | 5 | 3.75 | 10 |
Mumbai | 4 | - | 6.666667 | 10 | 12.5 |
Calcutta | 5 | 6.666667 | - | 12.5 | 12 |
Chennai | 3.75 | 10 | 12.5 | - | 4 |
Bangalore | 10 | 12.5 | 12 | 4 | - |
(c)
New answer posted
7 months agoContributor-Level 10
(b)
The total price of Guavas with Shweta is 5 * 28 = Rs. 140
The total price of the 26 Guavas whose price is not known is 140 – (3 + 8) = Rs. 129.
Assume that maximum number of Guavas with have price equal to Rs. 7
129 = 8 * 7 + 1 * 5 + 17 * 4. Therefore, the number of Guavas with Shweta whose price is less than the average price of the Guavas with Shweta is at least 17 + 1 = 18.
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