Electrostatic Potential and Capacitance
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Two charged thin infinite plane sheets of uniform surface charge density σ+and σ−, where |σ+| > |σ−|, intersect at right angle. Which of the following best represents the electric field lines for this system.
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Two charged thin infinite plane sheets of uniform surface charge density σ+and σ−, where |σ+| > |σ−|, intersect at right angle. Which of the following best represents the electric field lines for this system.
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A two point charges 4q and –q are fixed on the x-axis at x = −d/2 and x = d/2, respectively. If a third point charge ' q ' is taken from the origin to x = d along the semicircle as shown in the figure, the energy of the charge will:
A two point charges 4q and –q are fixed on the x-axis at x = −d/2 and x = d/2, respectively. If a third point charge ' q ' is taken from the origin to x = d along the semicircle as shown in the figure, the energy of the charge will:
Uinitial = k(4q)(q)/(d/2) + k(q)(-q)/(d/2)
⇒ 6kq²/d
⇒ Ufinal = k(4q)(q)/((3d/2)) + k(q)(-q)/(d/2)
⇒ 2kq²/3d
⇒ ΔU = (2/3 - 6)kq²/d = -16kq²/3d
<p><strong>Two small spherical balls of mass 10 g each with charges -2μC and 2μC, are attached to two ends of very light rigid rod of length 20 cm. The arrangement is now placed near an infinite nonconducting charge sheet with uniform charge density of 100μC/m² such that length of rod makes an angle of 30° with electric field generated by charge sheet. Net torque acting on the rod is: (Take ε? = 8.85 × 10?¹²C²/Nm²)</strong><br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Effective capacitance of parallel combination of two capacitors and is . When these capacitor are individually connected to a voltage source of , the energy stored in the capacitor is 4 times that of . If these capacitors are connected in series, their effective capacitance will be
Effective capacitance of parallel combination of two capacitors and is . When these capacitor are individually connected to a voltage source of , the energy stored in the capacitor is 4 times that of . If these capacitors are connected in series, their effective capacitance will be
Given:
From equation (i) and (ii)
If they are in series
In finding the electric field using Gauss law the formula is applicable. In the formula is permittivity of free space, is the area of Gaussain surface and is charge enclosed by the Gaussian surface. This equation can be used in which of the following situation? Only when the Gaussian surface is an
In finding the electric field using Gauss law the formula is applicable. In the formula is permittivity of free space, is the area of Gaussain surface and is charge enclosed by the Gaussian surface. This equation can be used in which of the following situation? Only when the Gaussian surface is an
Magnitude of electric field is constant & the surface is equipotential.
Find out the surface charge density at the intersection of point x = 3 m plane and x-axis, in the region of uniform line charge of 8 nC/m lying along the z-axis in free space.
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Find out the surface charge density at the intersection of point x = 3 m plane and x-axis, in the region of uniform line charge of 8 nC/m lying along the z-axis in free space.
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According to Question, we can write
E = λ/ (2πε? r) ⇒ σ = ε? E = λ/ (2πr)
⇒ σ = 8×10? / (2×3.14×3) = 0.424 nCm? ²
27 similar drops of mercury are maintained at 10V each. All these spherical drops combine into a single big drop. The potential energy of the bigger drop is……… times that of a smaller drop.
27 similar drops of mercury are maintained at 10V each. All these spherical drops combine into a single big drop. The potential energy of the bigger drop is……… times that of a smaller drop.
With the help of conservation of volume, we can write
With the help of conservation of charge, we can write
Q = 27 q.(2)
Potential energy of single drop = U1 =
Potential energy of bigger drop =
Two electrons each are fixed at a distance ‘2d’. A third charge proton placed at the midpoint is displaced slightly by a distance x (x << d) perpendicular to the line joining the two fixed charges. Proton will execute simple harmonic motion having angular frequency:
(m = mass of charged particle)
Two electrons each are fixed at a distance ‘2d’. A third charge proton placed at the midpoint is displaced slightly by a distance x (x << d) perpendicular to the line joining the two fixed charges. Proton will execute simple harmonic motion having angular frequency:
(m = mass of charged particle)
[for small displacement i.e, x is small so|, sin tan ]
[q = e]
512 identical drops of mercury are charged to a potential of 2V each. The drops are joined to form a single drop. The potential of this drop is ……………. V.
512 identical drops of mercury are charged to a potential of 2V each. The drops are joined to form a single drop. The potential of this drop is ……………. V.
Let the charge of on each drop be q and radius of each drop be r.
When all drops are joined, radius,
Potential of the new drop,


