Electrostatic Potential and Capacitance

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

C1 = k 1 ? A d 1  , C2 = k 2 ? A d 2

1 C = 1 C 1 + 1 C 2 = C 1 * C 2 C 1 + C 2 = k 1 k 2 ? A k 1 d 2 + k 2 d 1

K = k 1 k 2 ( d 1 + d 2 ) k 1 d 2 + k 2 d 1

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(a) The electric potential due to point charge q is given by V=q/4? 0r

It means electric potential due to point charge is same for all equidistant points. The locus of these equidistant points, which are at same potential, form spherical surface.

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(c) As we know that E= - d v d r and potential is always same through out the surface, so according to relation electric field is zero because potential remains same at each point.

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(c) As W=qdv=q (final potential-initial potential), but the potential at a and b is same in all cases . so work done is equal in all cases.

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(c) Electric potential are always less in the direction of electric field

E= - d v d r and W= qdv . so potential energy also decrease in the direction of electric field

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(d) We know that I=  v R + r = 2.5 2 + 0.5 = 1 A

The potential difference across 2 ohm = 1 (2)= 2V

As Q=CV = 4 * 2= 8 μC

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

Let us take a point p to be at a distance z from the center of ring

V=K d q r = k d q z 2 + a 2  = k z 2 + a 2 d q = k Q z 2 + a 2

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

Let us take a point p to be at a distance z from the center of ring

V=K d q r = k d q z 2 + a 2  = k z 2 + a 2 d q = k Q z 2 + a 2

 

U= w =qV= k Q ( - q ) z 2 + a 2 = - K Q q z 2 + a 2

Charge would perform oscillations.

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

According to the relation that E= - d v d r , potential always decrease in the direction of electric field . so if we go from any point to infinity that decreases the potential.

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

The capacitance of the parallel plate capacitor, with dielectric medium of dielectric constant K is given by, C=K? 0A/d

The capacitance of the parallel plate capacitor decreases with the removal of dielectric medium.

If we disconnect the battery from capacitor, then the charge stored will remain the same due to conservation of charge.

The energy stored in an isolated charge capacitor  U =q2/2C  as q is constant, energy stored U ∝ 1/C .As C decreases with the removal of dielectric medium, therefore energy stored increases.

The potential difference across the pla

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